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If a, b, and c are integer and ab + c is odd, which of the m [#permalink]
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17 Jan 2012, 07:05
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If a, b, and c are integer and ab + c is odd, which of the must be true? I. a + c is odd II. b + c is odd III. abc is even (A) I only (B) II only (C) III only (D) I and III only (E) II and III only I understand the reasoning behind the correct answer, but the MGMAT book's solution also uses a graph which I cannot understand (please see attached file). Can someone explain why under both a and b in the row for two, it is listed as Odd, and then Even for the c column? The book doesn't explain how it sets up the graph. Thanks
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Re: If a, b, and c are integer and ab + c is odd, which of the m [#permalink]
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17 Jan 2012, 07:33
rdevorse wrote: If a, b, and c are integer and ab + c is odd, which of the must be true? I. a + c is odd II. b + c is odd III. abc is even (A) I only (B) II only (C) III only (D) I and III only (E) II and III only I understand the reasoning behind the correct answer, but the MGMAT book's solution also uses a graph which I cannot understand (please see attached file). Can someone explain why under both a and b in the row for two, it is listed as Odd, and then Even for the c column? The book doesn't explain how it sets up the graph. Thanks They've listed all possible scenarios for a, b, and c. As each of them can be either even or odd (2 option for each) then there are total of 2*2*2=8 scenarios possible. Then they evaluated each, to see which scenario makes ab+c odd and after that picked these scenarios to work with options I, II, and III. Personally I'd approach this question in another way. \(ab+c=odd\), means: 1. \(ab=even\) (which means that at least one of them is even) and \(c=odd\); OR: 2. \(ab=odd\) (which means that both are odd) and \(c=even\). We can see that in both cases at least one is even thus option III (\(abc=even\)) is always true. Now, for I: if \(c=odd\) (case 1) and \(a=odd\) (so \(b=even\)) then \(a+c=even\neq{odd}\), so this option is not always true. Exactly the same for option II: if \(c=odd\) (case 1) and \(b=odd\) (so \(a=even\)) then \(b+c=even\neq{odd}\), so this option is not always true. Answer: C (III only). Hope it's clear.
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Re: If a, b, and c are integer and ab + c is odd, which of the m [#permalink]
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17 Jan 2012, 07:37
Ahhh, ok. Clearly, I missed the word "Scenario" on the top left corner lol. Now it makes sense. I do prefer your method. Thanks so much
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Re: If a, b, and c are integer and ab + c is odd, which of the m [#permalink]
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17 Jan 2012, 10:23
why are we not considering 0 for c?



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Re: If a, b, and c are integer and ab + c is odd, which of the m [#permalink]
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17 Jan 2012, 16:16



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Re: If a, b, and c are integer and ab + c is odd, which of the m [#permalink]
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29 Apr 2013, 16:15
rdevorse wrote: If a, b, and c are integer and ab + c is odd, which of the must be true? I. a + c is odd II. b + c is odd III. abc is even (A) I only (B) II only (C) III only (D) I and III only (E) II and III only I understand the reasoning behind the correct answer, but the MGMAT book's solution also uses a graph which I cannot understand (please see attached file). Can someone explain why under both a and b in the row for two, it is listed as Odd, and then Even for the c column? The book doesn't explain how it sets up the graph. Thanks Hi guys, Can we just do this by substituting, like I take say a=1,b=2 and c= 3 which gives ab+c = 5 , holds true for b+c is odd and abc is odd Secondly a=2,b=5 and c=7 gives ab+c=17, holds true for a+c is odd and abc is odd. Considering both we come to a conclusion that abc is odd alone. Hope that helps!




Re: If a, b, and c are integer and ab + c is odd, which of the m
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29 Apr 2013, 16:15








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