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If A, B and C are integers such that B>A, is B+C > A?

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If A, B and C are integers such that B>A, is B+C > A? [#permalink]

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25 Jan 2008, 11:08
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If A, B and C are integers such that B>A, is B+C > A?

1) C>A
2) ABC>0
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25 Jan 2008, 15:19
B>A

Is B+C>A?

1. C>A INSUFFICIENT because it doesn't take negative numbers into account
2. abc>0 we see all 3 terms are positive, or 2 are negative and 1 is positive. None of the terms = 0. nothing about the relationships so INSUFFICIENT

now taken together we have:

ABC > 0
B>A
C>A

Since we're doing addition the order doesn't matter on the little line below:

A<B<C

If all 3 are positive then B+C>A
If 2 are negative and 1 is positive then B+C>A

7-t58870
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26 Jan 2008, 11:16
C

from the second statement: there are three cases when abc>0

+ve*+ve*+ve. we know that b>a, and need to prove b+c>a. this would've been sufficient but in case when it is

-ve*-ve*+ve, we need to know the relation between c and a. first statement gives it
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26 Jan 2008, 13:00

Statement 1 : Insufficient

lets us say A=4 -4
B=6 -2
C=5 -3
B+C>A B+C<A

Statement 2 : Insufficient

let us say A=4 -4
B=5 -2
C=6 -3
B+C>A B+C<A

Both together

A=4 -3
B=6 -2
C=5 1
B+C>A B+C>A
Re: DS: Integers   [#permalink] 26 Jan 2008, 13:00
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