sharkr wrote:
VeritasPrepKarishma wrote:
Basically, you have to look for values such that when the numerators add up, the sum is divisible by the denominator. a and b cannot be 1 since we need the sum to be less than 1.
What are the numerators, the sum, and the denominator referring to?
Thanks in advance.
1/a + 1/b = 1/c
You have to look for values of a and b (denominators) such that when you add 1/a and 1/b, the numerator you get is divisible by the denominator of the fraction (which you get after adding)
e.g. if a = 3, b = 6
1/a + 1/b = 1/3 + 1/6 = (2 + 1)/6 = 3/6
The numerator is 3 and the denominator is 6. The numerator is divisible by the denominator such that you get 1 in the numerator after cancelling.
1/a + 1/b = 1/3 + 1/6 = 1/2
When you get 1 in the numerator, the denominator of the resulting fraction is the value of c (i.e. 2 above)
Thanks for the reply.
For clarification, don't you mean the denominator (ie. 6) is divisible by the numerator (ie. 3)?