Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 14:57

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If (a-b)/c<0, is a>b?

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Director
Joined: 03 Aug 2012
Posts: 896
Concentration: General Management, General Management
GMAT 1: 630 Q47 V29
GMAT 2: 680 Q50 V32
GPA: 3.7
WE: Information Technology (Investment Banking)
Followers: 24

Kudos [?]: 768 [0], given: 322

If (a-b)/c<0, is a>b? [#permalink]

### Show Tags

16 Mar 2013, 22:15
1
This post was
BOOKMARKED
00:00

Difficulty:

25% (medium)

Question Stats:

73% (01:59) correct 27% (01:23) wrong based on 62 sessions

### HideShow timer Statistics

If (a-b)/c<0, is a>b?

(1) c < 0
(2) a + b < 0
[Reveal] Spoiler: OA

_________________

Rgds,
TGC!
_____________________________________________________________________
I Assisted You => KUDOS Please
_____________________________________________________________________________

Last edited by Bunuel on 17 Mar 2013, 01:37, edited 1 time in total.
Renamed the topic and edited the question.
Director
Joined: 03 Aug 2012
Posts: 896
Concentration: General Management, General Management
GMAT 1: 630 Q47 V29
GMAT 2: 680 Q50 V32
GPA: 3.7
WE: Information Technology (Investment Banking)
Followers: 24

Kudos [?]: 768 [1] , given: 322

### Show Tags

16 Mar 2013, 22:20
1
KUDOS
(a-b)/c <0

=> c(a-b)/c^2 < 0
=> ac -bc <0
=> ac<bc

Statement (1) : Tells the sign of (C) means sufficient.

Statement (2) : a+b < 0

=> a < -b

a b a<-b Is a>b?
+ + Not Poss N/A
- - Yes No
- + Yes No
+ - Yes No

Why the answer is not (D).

Please tell what I am missing above

Rgds,
TGC
_________________

Rgds,
TGC!
_____________________________________________________________________
I Assisted You => KUDOS Please
_____________________________________________________________________________

Math Expert
Joined: 02 Sep 2009
Posts: 38908
Followers: 7739

Kudos [?]: 106243 [1] , given: 11618

Re: If (a-b)/c<0, is a>b? [#permalink]

### Show Tags

17 Mar 2013, 01:53
1
KUDOS
Expert's post
If (a-b)/c<0, is a>b?

(1) c < 0. Multiply (a-b)/c<0 by negative c and flip the sign a-b>0 --> a>b. Sufficient.

(2) a + b < 0. The sum of two numbers is less than zero. Can we tell which of them is greater? (Can we tell whether a>b or a<b?) No, consider a=1, b=-2 and c=-1 AND a=-2, b=1 and c=1. Not sufficient.

_________________
VP
Status: Final Lap Up!!!
Affiliations: NYK Line
Joined: 21 Sep 2012
Posts: 1083
Location: India
GMAT 1: 410 Q35 V11
GMAT 2: 530 Q44 V20
GMAT 3: 630 Q45 V31
GPA: 3.84
WE: Engineering (Transportation)
Followers: 38

Kudos [?]: 565 [1] , given: 70

### Show Tags

17 Mar 2013, 09:38
1
KUDOS
targetgmatchotu wrote:
Bunuel wrote:
targetgmatchotu wrote:
(a-b)/c <0

=> c(a-b)/c^2 < 0
=> ac -bc <0
=> ac<bc

Statement (1) : Tells the sign of (C) means sufficient.

Statement (2) : a+b < 0

=> a < -b

a b a<-b Is a>b?
+ + Not Poss N/A
- - Yes No
- + Yes No
+ - Yes No

Why the answer is not (D).

Please tell what I am missing above

Rgds,
TGC

Consider one of the cases in your approach above: if both a and b are negative, it's possible that a>b as well as a<b. For example, a=-1, b=-2, and c=-1 AND a=-2, b=-1, and c=1.

Hope it helps.

Why to take c variable in picture .

Given that a<-b
I think appropriate would be
a = -1
b = -2 (here a>b still holding a<-b)

a = -2
b = -1 (here a <b still holding a<-b)

Hence,wrong

Hi TGC
good to see you back on the forums..........people gather courage from life's storms.

I think the process you suggested is correct and has got no flaws in it....its concise...i do not find any use of third variable here.

Archit
Intern
Joined: 05 Mar 2013
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 39

Re: If (a-b)/c<0, is a>b? [#permalink]

### Show Tags

17 Mar 2013, 01:46
Before cross multiplying or multiplying numerator and denominator by c you should keep in mind that c should not be equal to 0
So which statement proves c won't be 0
(1) c < 0
This statement implies that c is not equal to 0
(2) a + b < 0
You aren't sure whether c would be 0 or not.
Hence, the answer should be A

Director
Joined: 03 Aug 2012
Posts: 896
Concentration: General Management, General Management
GMAT 1: 630 Q47 V29
GMAT 2: 680 Q50 V32
GPA: 3.7
WE: Information Technology (Investment Banking)
Followers: 24

Kudos [?]: 768 [0], given: 322

Re: If (a-b)/c<0, is a>b? [#permalink]

### Show Tags

17 Mar 2013, 07:14
Bunuel wrote:
If (a-b)/c<0, is a>b?

(1) c < 0. Multiply (a-b)/c<0 by negative c and flip the sign a-b>0 --> a>b. Sufficient.

(2) a + b < 0. The sum of two numbers is less than zero. Can we tell which of them is greater? (Can we tell whether a>b or a<b?) No, consider a=1, b=-2 and c=-1 AND a=-2, b=1 and c=1. Not sufficient.

What is wrong in the solution that I gave?

Rgds,
TGC
_________________

Rgds,
TGC!
_____________________________________________________________________
I Assisted You => KUDOS Please
_____________________________________________________________________________

Math Expert
Joined: 02 Sep 2009
Posts: 38908
Followers: 7739

Kudos [?]: 106243 [0], given: 11618

### Show Tags

17 Mar 2013, 07:54
targetgmatchotu wrote:
(a-b)/c <0

=> c(a-b)/c^2 < 0
=> ac -bc <0
=> ac<bc

Statement (1) : Tells the sign of (C) means sufficient.

Statement (2) : a+b < 0

=> a < -b

a b a<-b Is a>b?
+ + Not Poss N/A
- - Yes No
- + Yes No
+ - Yes No

Why the answer is not (D).

Please tell what I am missing above

Rgds,
TGC

Consider one of the cases in your approach above: if both a and b are negative, it's possible that a>b as well as a<b. For example, a=-1, b=-2, and c=-1 AND a=-2, b=-1, and c=1.

Hope it helps.
_________________
Director
Joined: 03 Aug 2012
Posts: 896
Concentration: General Management, General Management
GMAT 1: 630 Q47 V29
GMAT 2: 680 Q50 V32
GPA: 3.7
WE: Information Technology (Investment Banking)
Followers: 24

Kudos [?]: 768 [0], given: 322

### Show Tags

17 Mar 2013, 09:10
Bunuel wrote:
targetgmatchotu wrote:
(a-b)/c <0

=> c(a-b)/c^2 < 0
=> ac -bc <0
=> ac<bc

Statement (1) : Tells the sign of (C) means sufficient.

Statement (2) : a+b < 0

=> a < -b

a b a<-b Is a>b?
+ + Not Poss N/A
- - Yes No
- + Yes No
+ - Yes No

Why the answer is not (D).

Please tell what I am missing above

Rgds,
TGC

Consider one of the cases in your approach above: if both a and b are negative, it's possible that a>b as well as a<b. For example, a=-1, b=-2, and c=-1 AND a=-2, b=-1, and c=1.

Hope it helps.

Why to take c variable in picture .

Given that a<-b
I think appropriate would be
a = -1
b = -2 (here a>b still holding a<-b)

a = -2
b = -1 (here a <b still holding a<-b)

Hence,wrong
_________________

Rgds,
TGC!
_____________________________________________________________________
I Assisted You => KUDOS Please
_____________________________________________________________________________

Re: Inequalities   [#permalink] 17 Mar 2013, 09:10
Similar topics Replies Last post
Similar
Topics:
If a^3*b^4*c^5<0, is abc<0? 3 28 Nov 2016, 01:36
2 If abc ≠ 0, is a > 0? (1) 3*a/b > 0 (2) b/c^2 < 0 4 24 Feb 2017, 04:47
3 If c≠0 and (a*b)/c < 0, is a/c < 0 4 04 Dec 2016, 00:09
8 If a^5b^3c^6 < 0, is abc < 0? 6 07 Dec 2016, 09:27
1 If [(a-b)/c] < 0, is a > b ? (1) c < 0 (2) a+b < 0 3 31 May 2010, 11:50
Display posts from previous: Sort by

# If (a-b)/c<0, is a>b?

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.