stonecold wrote:

If A, B, C are integers and \(\sqrt{ABC}=504\) . Is B divisible by 2?

(1) C = 168

(2) A is a perfect square

Now solve this one=>

http://gmatclub.com/forum/is-b-divisibl ... l#p1726368Hi

stonecold good Q as so many are making errors..

The value of B can be only 1or 3 is WRONG..

Let's see the Q..

\(\sqrt{ABC}=504\) MEANS A*B*C=504*504...

So if C =168, A*B=\(\frac{504*504}{168}\)=1512..

So A and B can take various combinations of values..

So statement I is insufficient...

Statement II doesn't give any info alone so again insufficient..

Combined..

A*B=1512=\(3^3*7*2^3\)...

So if A is perfect square, A can have either 2^2 or no 2 in it..

Thus B has to have ATLEAST one 2..

Thus answer is YES..

Sufficient

C

Is there a faster approach other than calculating A*B=\(\frac{504*504}{168}\)=1512? Wouldn't be able to do this question in 2 mins...