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If a + b + c + d is a positive number, a minimum of x of the numbers

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If a + b + c + d is a positive number, a minimum of x of the numbers [#permalink]

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If a + b + c + d is a positive number, a minimum of x of the numbers a, b, c, and d must be positive where x is equal to

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
[Reveal] Spoiler: OA

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Kudos [?]: 135382 [1], given: 12691

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Re: If a + b + c + d is a positive number, a minimum of x of the numbers [#permalink]

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New post 30 Oct 2017, 21:16
Bunuel wrote:
If a + b + c + d is a positive number, a minimum of x of the numbers a, b, c, and d must be positive where x is equal to

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4


If (d) > absolute value of l(a+b+c)l where d is positive, then x=1.

Answer B.

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Re: If a + b + c + d is a positive number, a minimum of x of the numbers [#permalink]

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New post 01 Nov 2017, 16:07
The question asks for the minimum positive number so that the sum can be positive.
Out of the given options, the minimum positive number is 1.
Hence answer is B.

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Re: If a + b + c + d is a positive number, a minimum of x of the numbers [#permalink]

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New post 01 Nov 2017, 21:33
The question ask about minimum positive numbers
take example that one number is 100 and other three number is -1 so minimum number should be 1
So answer should be B
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Kudos [?]: 101 [0], given: 59

Re: If a + b + c + d is a positive number, a minimum of x of the numbers   [#permalink] 01 Nov 2017, 21:33
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