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# If a code word is defined to be a sequence of different

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Senior Manager
Joined: 02 Dec 2007
Posts: 449

Kudos [?]: 280 [0], given: 6

If a code word is defined to be a sequence of different [#permalink]

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19 Sep 2008, 10:25
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

A. 5 to 4
B. 3 to 2
C. 2 to 1
D. 5 to 1
E. 6 to 1

Kudos [?]: 280 [0], given: 6

Intern
Joined: 02 Sep 2008
Posts: 45

Kudos [?]: [0], given: 0

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19 Sep 2008, 10:28
I come up with E. It is 6 to 1.

Kudos [?]: [0], given: 0

SVP
Joined: 21 Jul 2006
Posts: 1513

Kudos [?]: 978 [0], given: 1

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19 Sep 2008, 19:17
Nihit wrote:
If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

A. 5 to 4
B. 3 to 2
C. 2 to 1
D. 5 to 1
E. 6 to 1

I got E as well:

5-letter code: 10*9*8*7*6
4-letter code: 10*9*8*7

Therefore, the ratio is: (10*9*8*7*6)/(10*9*8*7) = 6/1

Kudos [?]: 978 [0], given: 1

Director
Joined: 23 May 2008
Posts: 803

Kudos [?]: 82 [0], given: 0

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20 Sep 2008, 00:12
why do we use permutation here and not combination?

Kudos [?]: 82 [0], given: 0

Re: code word   [#permalink] 20 Sep 2008, 00:12
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