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Re: If a equals the sum of the even integers from 2 to 200, inclusive, and [#permalink]
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Drik wrote:
If a equals the sum of the even integers from 2 to 200, inclusive, and b equals the sum of the odd integers from 1 to 199, inclusive, what is the value of a - b?

A. 10
B. 100
C. 190
D. 200
E. 210


Similar questions to practice:
if-x-is-equal-to-the-sum-of-the-integers-from-30-to-127276.html (MGMAT)
if-m-equals-the-sum-of-the-even-integers-from-2-to-128426.html
if-x-is-equal-to-the-sum-of-the-even-integers-from-40-to-97544.html

Hope it helps.
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Re: If a equals the sum of the even integers from 2 to 200, inclusive, and [#permalink]
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PROBLEM:
If a equals the sum of the even integers from 2 to 200, inclusive, and b equals the sum of the odd integers from 1 to 199, inclusive, what is the value of a - b?

A. 10
B. 100
C. 190
D. 200
E. 210


SOLUTION:

Use following formulae for such problems:

Sum of evenly spaced integers = (# of integers)*(mean of integers)

# of integers = [(last - first)/2] + 1
Mean of integers = (last + first)/2

In above problem:

# of integers = [(200 - 2)/2] + 1= 100 and [(199-1)/2]+ 1 = 100
Mean of integers = (200 + 2) = 101 and (199 + 1)/2 = 100

Sum of integers = (101*100) = 10100 and (100*100) = 10000

Thus their difference (a - b) = 100

ANSWER:B
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Re: If a equals the sum of the even integers from 2 to 200, inclusive, and [#permalink]
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A: 2,4,6,8,10,12,14

B: 1,3,5,7, 9, 11,13

see that every number in A is exactly 1 more than such number in B.

difference is exactly the number of term in A and B and it is 100

B
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Re: If a equals the sum of the even integers from 2 to 200, inclusive, and [#permalink]
if we have 100 even and 100 odd then the difference between the sum of even ones and odds one will be 100.
logically thinking, each even number will be 1 more than preceded odd number. since we have 100 even numbers, then the difference is 100.
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Re: If a equals the sum of the even integers from 2 to 200, inclusive, and [#permalink]
Here is my solution to this one =>
a= 100/1[2+200] = 50*202
b= 100/2[1+199]=50*200

Hence a-b= 50[202-200] = 50*2 = 100

Hence B
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Re: If a equals the sum of the even integers from 2 to 200, inclusive, and [#permalink]
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Re: If a equals the sum of the even integers from 2 to 200, inclusive, and [#permalink]
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