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If a is a positive integer less than 3 and b is a positive integer les [#permalink]

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23 Sep 2016, 04:19

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If a is a positive integer less than 3 and b is a positive integer less than 11, what is the value of the decimal expression of a/b when rounded to the nearest tenths?

(1) When the decimal expression of a/b is rounded to the nearest hundredths the value of the hundredths digit is 1. (2) When the decimal expression of a/b is rounded to the nearest ten-thousandths the value of the ten-thousandths digit is 9.

If a is a positive integer less than 3 and b is a positive integer les [#permalink]

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23 Sep 2016, 04:55

duahsolo wrote:

If a is a positive integer less than 3 and b is a positive integer less than 11, what is the value of the decimal expression of a/b when rounded to the nearest tenths?

(1) When the decimal expression of a/b is rounded to the nearest hundredths the value of the hundredths digit is 1. (2) When the decimal expression of a/b is rounded to the nearest ten-thousandths the value of the ten-thousandths digit is 9.

Answer D.

We are given a = 1 or 2

b could be 1,2,3,.. 10

Now, Statement 1 : Only fraction that could give the value of hundredths digit 1 is 1/9. So, Sufficient.

Statement 2 : Only fraction that could give the value of ten-thousandths digit 9 is 1/7. So, Sufficient.
_________________

Re: If a is a positive integer less than 3 and b is a positive integer les [#permalink]

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23 Sep 2016, 04:59

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a < 3; b < 11; a/b rounded to nearest tenths = ?

St1: Rounding to nearest hundredth, a/b = 0._1 Put a = 2 and plug values of b from 3 to 10 --> Rounding to the hundredths digit does not result in 1. a = 1; b = 10 --> a/b = 0.1 --> Not possible a = 1; b = 9 --> a/b = 0.11 --> Possible a = 1; b = 8 --> a/b = 0.13 --> Not possible As b decreases value of a/b increases and hundredths digit does not equal to 1 --> Only possible value of a/b = 0.11 Value of a/b rounded to nearest tenth = 0.1 Sufficient

St2: Rounding to nearest ten thousandth, a/b = 0._ _ _ 9 We need a recurring values to find this Possible values = 2/3 = 1/6 = 0.6667 --> Not possible 2/6 = 1/3 = 0.3333 --> Not possible 2/7 = 0.28571 = 0.2857 --> Not possible 2/9 = 0.2222; 1/9 = 0.1111 --> Not possible 1/7 = 0.14285 = 0.1429 --> Possible a/b rounded to the nearest tenth = 0.1 Sufficient

Re: If a is a positive integer less than 3 and b is a positive integer les [#permalink]

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23 Sep 2016, 05:01

abhimahna wrote:

duahsolo wrote:

If a is a positive integer less than 3 and b is a positive integer less than 11, what is the value of the decimal expression of a/b when rounded to the nearest tenths?

(1) When the decimal expression of a/b is rounded to the nearest hundredths the value of the hundredths digit is 1. (2) When the decimal expression of a/b is rounded to the nearest ten-thousandths the value of the ten-thousandths digit is 9.

Answer D.

We are given a = 1 or 2

b could be 1,2,3,.. 10

Now, Statement 1 : Only fraction that could give the value of hundredths digit 1 is 1/9. So, Sufficient.

Statement 2 : Only fraction that could give the value of ten-thousandths digit 9 is 1/9. So, Sufficient.

Small correction. The above highlighted part must be 1/7.

Re: If a is a positive integer less than 3 and b is a positive integer les [#permalink]

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23 Sep 2016, 05:15

Vyshak wrote:

abhimahna wrote:

duahsolo wrote:

If a is a positive integer less than 3 and b is a positive integer less than 11, what is the value of the decimal expression of a/b when rounded to the nearest tenths?

(1) When the decimal expression of a/b is rounded to the nearest hundredths the value of the hundredths digit is 1. (2) When the decimal expression of a/b is rounded to the nearest ten-thousandths the value of the ten-thousandths digit is 9.

Answer D.

We are given a = 1 or 2

b could be 1,2,3,.. 10

Now, Statement 1 : Only fraction that could give the value of hundredths digit 1 is 1/9. So, Sufficient.

Statement 2 : Only fraction that could give the value of ten-thousandths digit 9 is 1/9. So, Sufficient.

Small correction. The above highlighted part must be 1/7.

Yeah, it was a typo. Its 1/7 .

Edited the original solution. Thanks
_________________

Re: If a is a positive integer less than 3 and b is a positive integer les [#permalink]

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23 Feb 2017, 05:04

Prompt analysis a<3 and b<11

Superset The answer will be a positive single digit.

Translation

In order to find the digit, we need: 1# exact value of a and b. 2# the properties of a/b. 3# two equation to find a and b.

Statement Analysis St1: Rounding to nearest hundredth, a/b = 0._1 Put a = 2 and plug values of b from 3 to 10 --> Rounding to the hundredths digit does not result in 1. a = 1; b = 10 --> a/b = 0.1 --> Not possible a = 1; b = 9 --> a/b = 0.11 --> Possible a = 1; b = 8 --> a/b = 0.13 --> Not possible As b decreases value of a/b increases and hundredths digit does not equal to 1 --> Only possible value of a/b = 0.11 Value of a/b rounded to nearest tenth = 0.1 Sufficient

St2: Rounding to nearest ten thousandth, a/b = 0._ _ _ 9 We need a recurring values to find this Possible values = 2/3 = 1/6 = 0.6667 --> Not possible 2/6 = 1/3 = 0.3333 --> Not possible 2/7 = 0.28571 = 0.2857 --> Not possible 2/9 = 0.2222; 1/9 = 0.1111 --> Not possible 1/7 = 0.14285 = 0.1429 --> Possible a/b rounded to the nearest tenth = 0.1 Sufficient

Re: If a is a positive integer less than 3 and b is a positive integer les [#permalink]

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24 May 2017, 09:26

Quick question: I've read somewhere that statements 1 and 2, while they must be analysed separate from each other, they do need to be consistent, meaning that if answer is D-EACH, then the solution found must be the same.

Is this not true? Cause this problem goes against that...