Abhi077 wrote:
If a is an integer greater than zero, then a(a + 1)(a + 3) is
A) Even only when a is even
B) Even only when a is odd
C) odd whenever a is odd
D) Divisible by 3 only when a is odd
E) Divisible by 4 whenever a is odd
Now a and a+1 are consecutive integers, so the product a(a+1)(a+3) will always be even..
Choices A,B and C are out
Now, a, a+1, a+2, a+3 are 4 consecutive integers, so one of them is surely a multiple of 3..
If a is a multiple of 3, the product will also be a multiple of 3.. but X can be 3 or 6 too
So eliminate D
Ans is E
Let's see
When a is ODD a+1and a+3 both will be even , so the product will be a multiple of 4... Rather a multiple of atleast 8
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