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Re: If a, m and n are positive integers, is n^(2a) a multiple of [#permalink]

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06 Jul 2014, 22:27

1

This post was BOOKMARKED

The question basically asks if n^2a/m^a =integer,is (n^a.n^a)/m^a =integer,is (n/m)^a.n^a=integer,since n and a are positive integer,it will always be an integer,so the question really is n a multiple of m then only (n/m)^a.n^a=integer

Statement 1 n/(m/2)=integer↪2n/m=integer↪n=1,m=2 then n/m≠integer↪↪but n=2,m=1,then n/m=integer…not sufficient

Re: If a, m and n are positive integers, is n^(2a) a multiple of [#permalink]

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08 Jul 2015, 02:28

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Re: If a, m and n are positive integers, is n^(2a) a multiple of [#permalink]

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07 Sep 2016, 06:36

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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