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If a spaceship travels at an average speed of 6*10^10 kilometers per

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If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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New post 23 Aug 2018, 23:52
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C
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Question Stats:

79% (00:52) correct 21% (02:22) wrong based on 53 sessions

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If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?


A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21

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If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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New post 23 Aug 2018, 23:57
Bunuel wrote:
If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?


A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21


\(Time(in years)=\frac{Distance}{Speed}=\frac{3*10^{30}}{6*10^{10}}\)=\(5*10^{19}\)

Ans. (C)
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If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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New post 24 Aug 2018, 03:45
Bunuel wrote:
If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?


A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21


Average speed = \(6*10^{10}\)

Distance need to travel = \(3*10^{30}\)

Time =\(\frac{Distance}{Speed}\)

\(\frac{3*10^{30}}{6*10^{10}}\)

=\(\frac{1}{2}\) * \(10^{20}\)

= 0.5 * \(10^{20}\)

= \(5 * 10^{19}\)

The best answer is C.
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Re: If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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New post 24 Aug 2018, 06:43
Bunuel wrote:
If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?


A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21


\(= \frac{3*10^{30}}{6*10^{10}}\)

\(= \frac{3*10^{20}}{6}\)

\(= \frac{30*10^{19}}{6}\)

\(= 5*10^{19}\) , Answer must be (C)
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Re: If a spaceship travels at an average speed of 6*10^10 kilometers per &nbs [#permalink] 24 Aug 2018, 06:43
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