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# If a spaceship travels at an average speed of 6*10^10 kilometers per

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Math Expert
Joined: 02 Sep 2009
Posts: 51302
If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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23 Aug 2018, 23:52
00:00

Difficulty:

15% (low)

Question Stats:

79% (00:52) correct 21% (02:22) wrong based on 53 sessions

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If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?

A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21

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If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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23 Aug 2018, 23:57
Bunuel wrote:
If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?

A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21

$$Time(in years)=\frac{Distance}{Speed}=\frac{3*10^{30}}{6*10^{10}}$$=$$5*10^{19}$$

Ans. (C)
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PKN

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If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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24 Aug 2018, 03:45
Bunuel wrote:
If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?

A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21

Average speed = $$6*10^{10}$$

Distance need to travel = $$3*10^{30}$$

Time =$$\frac{Distance}{Speed}$$

$$\frac{3*10^{30}}{6*10^{10}}$$

=$$\frac{1}{2}$$ * $$10^{20}$$

= 0.5 * $$10^{20}$$

= $$5 * 10^{19}$$

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Re: If a spaceship travels at an average speed of 6*10^10 kilometers per  [#permalink]

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24 Aug 2018, 06:43
Bunuel wrote:
If a spaceship travels at an average speed of 6*10^10 kilometers per year, how many years will it take the spaceship to travel 3*10^30 kilometers?

A. 5*10^2
B. 10^11
C. 5*10^19
D. 5*10^20
E. 5*10^21

$$= \frac{3*10^{30}}{6*10^{10}}$$

$$= \frac{3*10^{20}}{6}$$

$$= \frac{30*10^{19}}{6}$$

$$= 5*10^{19}$$ , Answer must be (C)
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Abhishek....

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Re: If a spaceship travels at an average speed of 6*10^10 kilometers per &nbs [#permalink] 24 Aug 2018, 06:43
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