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# If an integer n is to be chosen at random from the integers

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Senior Manager
Joined: 14 Jul 2006
Posts: 281

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If an integer n is to be chosen at random from the integers [#permalink]

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22 Aug 2006, 09:41
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?

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Manager
Joined: 25 Jul 2006
Posts: 99

Kudos [?]: 14 [0], given: 0

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22 Aug 2006, 09:52
total ways to select n = 94

# of multiples of 8 from 1-96 = 12
These can be either n, n+1, n+2 => # of possible combinations = 12*3 = 36

also if either n or n+2 is a multiple of 4; the product will be a multiple of 8;
so # of multiple of 4 from 1-96 = 24; # of distinct multiples of 4 = 12
and these nos can be either n or n+2 => # of combinations = 12*2

so total = 60/94

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Senior Manager
Joined: 14 Jul 2006
Posts: 281

Kudos [?]: 3 [0], given: 0

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22 Aug 2006, 09:54
hey ur ryt on the money with the official answer except i think ur denominator should be 96 not 94
Thanks

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22 Aug 2006, 09:54
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# If an integer n is to be chosen at random from the integers

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