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# If an integer n is to be chosen at random from the integers

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Joined: 06 Nov 2006
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If an integer n is to be chosen at random from the integers [#permalink]

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13 Nov 2006, 08:20
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If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?
A. 1/4
B. 3/8
C. 1/2
D. 5/8
E. 3/4

I don't really understand why the answer is 5/8...

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Senior Manager
Joined: 08 Jun 2006
Posts: 335

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Location: Washington DC

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13 Nov 2006, 10:05
5/8 ?
when n is even ..n (n+1)(n+2) is divisible by 8
Other cases are when n+1 is divisible by 8. Number of such cases = 12

so 96/2 +12 = 60

P = 60/96= 5/8

Kudos [?]: 63 [0], given: 0

13 Nov 2006, 10:05
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