Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 15:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If an integer n is to be chosen at random from the integers

Author Message
TAGS:

### Hide Tags

VP
Joined: 26 Apr 2004
Posts: 1213
Location: Taiwan
Followers: 2

Kudos [?]: 687 [1] , given: 0

If an integer n is to be chosen at random from the integers [#permalink]

### Show Tags

28 Aug 2004, 10:58
1
KUDOS
3
This post was
BOOKMARKED
00:00

Difficulty:

95% (hard)

Question Stats:

39% (02:06) correct 61% (01:51) wrong based on 118 sessions

### HideShow timer Statistics

If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?

A. 1/4
B. 3/8
C. 1/2
D. 5/8
E. 3/4

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-an-integer-n-is-to-be-chosen-at-random-from-the-integers-126654.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 25 Sep 2013, 04:53, edited 1 time in total.
Edited the question and added the OA
Senior Manager
Joined: 05 Feb 2004
Posts: 290
Location: USA
Followers: 1

Kudos [?]: 5 [0], given: 0

### Show Tags

28 Aug 2004, 14:31
Only even values of "n" satisfy and there are 48 even numbers between 1 to 96 inclusive....hence prob = 48/96 = 1/2....??
Senior Manager
Joined: 25 Jul 2004
Posts: 273
Followers: 1

Kudos [?]: 10 [0], given: 0

### Show Tags

28 Aug 2004, 18:38
Im gonna guess 3/4's.
If it has a multiple of eight, it works (obviously),
or if it has a multiple of 4 and an even number.

It is definately more than 1/2.
VP
Joined: 26 Apr 2004
Posts: 1213
Location: Taiwan
Followers: 2

Kudos [?]: 687 [0], given: 0

### Show Tags

29 Aug 2004, 02:16
Hi, SigEpUCI

In my opinion, if we randomly choose an interger which is the multiple of 2, n (n+1) (n+2) must be divided by 8.

Hence, the probability, I supposed, is 48/96 = 1/2.

Anything wrong?
Senior Manager
Joined: 19 May 2004
Posts: 291
Followers: 1

Kudos [?]: 15 [2] , given: 0

### Show Tags

29 Aug 2004, 09:33
2
KUDOS
I pick D. 5/8

Every threesome where the middle number is odd works
For example
2,3,4 Works.
4,5,6 Works.

Those account for 1/2 of the cases.

But remember that evert threesome where the middle number is divisible by 8 also works!
Example:
7,8,9 Works.
15,16,17.

Those account for 12/96 of the cases which is: 1/8.

1/2 + 1/8 = 5/8.
VP
Joined: 26 Apr 2004
Posts: 1213
Location: Taiwan
Followers: 2

Kudos [?]: 687 [0], given: 0

### Show Tags

30 Aug 2004, 07:20
Dookie wrote:
I pick D. 5/8

Every threesome where the middle number is odd works
For example
2,3,4 Works.
4,5,6 Works.

Those account for 1/2 of the cases.

But remember that evert threesome where the middle number is divisible by 8 also works!
Example:
7,8,9 Works.
15,16,17.

Those account for 12/96 of the cases which is: 1/8.

1/2 + 1/8 = 5/8.

well done, Dookie,

thank you
SVP
Joined: 16 Oct 2003
Posts: 1805
Followers: 5

Kudos [?]: 154 [0], given: 0

### Show Tags

02 Sep 2004, 09:58
I got 1/2.

Excellent explaination Dookie.
Manager
Joined: 10 Sep 2013
Posts: 80
Followers: 0

Kudos [?]: 73 [3] , given: 2

Re: If an integer n is to be chosen at random from the integers [#permalink]

### Show Tags

25 Sep 2013, 04:50
3
KUDOS
chunjuwu wrote:
If an integer n is to be chosen at random from the integers 1 to 96, inclusive,
what is the probability that n(n + 1)(n + 2) will be divisible by 8?

A. 1/4
B. 3/8
C. 1/2
D. 5/8
E. 3/4

For n(n+1)(n+2) to be divisible by 8, either n has to be even ( because if, n and n+2 are even, then n is divisible by 8) or n+1 as a whole should be divisible by 8
There are 96 values for n. The possibility of n to be even is (96/2) = 48 and the possibility of n to be divisible by 8 is (96/8)= 12
Therefore the total prob = (48+12)/96 = 60/96 = 5/8

The OA is D
_________________

Kudos if I helped

Math Expert
Joined: 02 Sep 2009
Posts: 38908
Followers: 7739

Kudos [?]: 106244 [0], given: 11618

Re: If an integer n is to be chosen at random from the integers [#permalink]

### Show Tags

25 Sep 2013, 04:53
OPEN DISCUSSION OF THIS QUESTION IS HERE: if-an-integer-n-is-to-be-chosen-at-random-from-the-integers-126654.html
_________________
Re: If an integer n is to be chosen at random from the integers   [#permalink] 25 Sep 2013, 04:53
Similar topics Replies Last post
Similar
Topics:
257 If an integer n is to be chosen at random from the integers 33 07 Feb 2017, 12:26
6 If an integer n is to be chosen at random from the integers 8 17 Oct 2014, 08:23
3 If an integer n is to be chosen at random from the integers 19 20 Apr 2015, 08:16
30 If an integer n is to be chosen at random from the integers 20 12 May 2017, 04:45
29 If an integer n is to be chosen at random from the integers 9 26 Jul 2014, 09:25
Display posts from previous: Sort by