It is currently 24 Jun 2017, 09:15

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If arc PQR is a semicircle, what is the diameter PR? 1) a=4

Author Message
Director
Joined: 17 Sep 2005
Posts: 903
If arc PQR is a semicircle, what is the diameter PR? 1) a=4 [#permalink]

### Show Tags

16 Jun 2006, 09:39
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If arc PQR is a semicircle, what is the diameter PR?
1) a=4
2) b=1

Regards,
Brajesh
Attachments

Q_Arc.GIF [ 1.39 KiB | Viewed 939 times ]

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

### Show Tags

16 Jun 2006, 10:07

Angle PQR = 90 degrees

St1:
Let b be x, can use pythagora's therem to solve for x and hence hte dimeter.

St2:
Let a be x, and using the same method to solve for x.
Manager
Joined: 15 Jun 2006
Posts: 69
Location: Seoul

### Show Tags

16 Jun 2006, 10:23
because if either part of the triangle (left or right) is set,
the remaining part will be determined.

However, I feel hard to prove it.
_________________

You go, we go

Intern
Joined: 01 Jun 2006
Posts: 22
Location: Toronto

### Show Tags

16 Jun 2006, 10:38
hm.....until you guys gave me the answer, I didn't know what to do.
But I think I know how to prove.
Let's make the point, where line a and b meet, W.
If you look carefully, triangle PQW is similiar to triangle PQR.
Then, you can use the ratio to solve this problem by using statement 1 and statement 2 seperately (Triangle PQR is also similar to triangle QWR)
I used the pythagora's theory to get line PQ, not for the entire problem.
But...when can I solve this kind of problem without getting an answer? Bad...
Director
Joined: 17 Sep 2005
Posts: 903

### Show Tags

16 Jun 2006, 10:44
fankor wrote:
hm.....until you guys gave me the answer, I didn't know what to do.

This was nice fankor

fankor wrote:

But...when can I solve this kind of problem without getting an answer? Bad...

This is again

Well I can only say Practice, Practice and more Practice.

Regards,
Brajesh
CEO
Joined: 20 Nov 2005
Posts: 2894
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

### Show Tags

16 Jun 2006, 12:35
This is D.

Lets call point which is between P and R on the diameter as X.

Angle PQR = 90, QX = 2

St1: a = 4 then PQX can be found. Then we can find XQR and in turn can find b. SUFF

St2: b = 1 then RQX can be found. Then we can find XQP and in turn can find a. SUFF
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

16 Jun 2006, 12:35
Display posts from previous: Sort by