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# If b and c are positive numbers and 1/b=b/c=c/8 , then b + c

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Manager
Joined: 07 Jul 2003
Posts: 56

Kudos [?]: 1 [0], given: 0

If b and c are positive numbers and 1/b=b/c=c/8 , then b + c [#permalink]

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10 Feb 2004, 14:47
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0% (00:00) correct 0% (00:00) wrong based on 5 sessions

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If b and c are positive numbers and 1/b=b/c=c/8 , then b + c =
(A) 4
(B) 6
(C) 7
(D) 8
(E) 9
_________________

Attain Moksha

Kudos [?]: 1 [0], given: 0

Manager
Joined: 07 Jul 2003
Posts: 56

Kudos [?]: 1 [0], given: 0

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10 Feb 2004, 15:15
I did get B too..But a long way..

where C^3=64 and so on..

Is this the only way...
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Attain Moksha

Kudos [?]: 1 [0], given: 0

Senior Manager
Joined: 05 May 2003
Posts: 424

Kudos [?]: 12 [0], given: 0

Location: Aus

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10 Feb 2004, 15:20
I did it this way.

1/b=b/c => b^2 =c

b/c=c/8 => c^2 =8b

then squared the first one b^4 = c^2
then substituted the second one b^4 = 8b
so, b^3= 8 => b=2

Kudos [?]: 12 [0], given: 0

10 Feb 2004, 15:20
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# If b and c are positive numbers and 1/b=b/c=c/8 , then b + c

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