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# If digit h is the hundredths' digit in the decimal d =

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If digit h is the hundredths' digit in the decimal d = [#permalink]

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19 Oct 2004, 13:13
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If digit h is the hundredths' digit in the decimal d = 0.2h6, what is the value of d, rounded to the nearest tenth?

(1) d < 1/4

(2) h < 5

According to the ETS Official Guide, the answer to this question is that both (1) & (2) are sufficient. The Guide says that so long as you can tell whether h < 5 or h >= 5 you can solve the problem. Obviously, (1) & (2) enable us to tell that h < 5. However, I thought the answer is that neither are sufficient because if h = 4 then the 6 causes it to round up to 5 and therefore d = 0.3 when rounded to the nearest tenth. Am I missing something? Thanks in advance for your help.
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19 Oct 2004, 20:45
Interesting... I see your point, and I agree.. anybody else think so?...
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19 Oct 2004, 22:31
[edited] yes, I agree with Dharmin. Let me try explain the confusion.

If I am corect, the confusion is around if h = 4.

d = 0.2h6

If h = 4, and you want to round to the nearest tenth, then d = 0.2. You don't first round the hundredth and then round the tenth - a sort of 'double rounding'.

(If h = 4, and you want to round to the nearest hundredth, then d = 0.25).

As far as the first condition, if d<.25, then it could be 0.24, 0.23, 0.22...and these rounded to the tenth, gets you d = 0.2

I hope that helps.

Last edited by Dan on 19 Oct 2004, 23:39, edited 1 time in total.
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Re: DS - Rounding Problem [#permalink]

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19 Oct 2004, 22:53
achuard wrote:
If digit h is the hundredths' digit in the decimal d = 0.2h6, what is the value of d, rounded to the nearest tenth?

(1) d < 1/4

(2) h < 5

According to the ETS Official Guide, the answer to this question is that both (1) & (2) are sufficient. The Guide says that so long as you can tell whether h < 5 or h >= 5 you can solve the problem. Obviously, (1) & (2) enable us to tell that h < 5. However, I thought the answer is that neither are sufficient because if h = 4 then the 6 causes it to round up to 5 and therefore d = 0.3 when rounded to the nearest tenth. Am I missing something? Thanks in advance for your help.

Correct yar, answer should be "Each statement is individually sufficient to answer the question"
If we construe "d, rounded to the nearest tenth" - meaning d = 0.2 , 0.3 , 0.4 , 0.5 ...
As we know, Rounding means adding up 1 if the next number is > 5.
Both choices say, h (which is next to 2) is < 5.
So in any case you need not to add 1 and thus you can easily say d = 0.2 after rounding it to nearest ten.

hope i am clear enough
Dharmin
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Perseverance, Hard Work and self confidence

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20 Oct 2004, 22:27
Quote:
[edited] yes, I agree with Dharmin. Let me try explain the confusion.

If I am corect, the confusion is around if h = 4.

d = 0.2h6

If h = 4, and you want to round to the nearest tenth, then d = 0.2. You don't first round the hundredth and then round the tenth - a sort of 'double rounding'.

(If h = 4, and you want to round to the nearest hundredth, then d = 0.25).

As far as the first condition, if d<.25, then it could be 0.24, 0.23, 0.22...and these rounded to the tenth, gets you d = 0.2

I agree with Dan. No double rounding....
20 Oct 2004, 22:27
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