Method 1:The square's vertices divide the circle's circumference (360°) into 4 equal arcs of 90° each.

The angle x is an inscribed angle that defines an arc that is made of three 90° arcs (BC, CD, DA).

Hence, x defines a 3×90° arc.

Remember: The arc is twice the inscribed angle that defines itSo, the angle x is half the 3×90° arc --> x = 3×45° = 135°

Answer D.Method 2:We know that ∠DEB = 90 (angle subtended at the circumference by the diameter is always 90º).

So, ∠AEB is surely > 90.

Option A and B out.∠AEB will surely be <180. (obvious reasons)

Option E is out.We are now left with 120 and 135. Now, draw the same figure on paper to guess that the angle will be mostly greater than 120.

I did the same thing and guessed D in 30 secs.

Hope you find this helpful.

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P.S. Don't forget to give kudos

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P.S. Don't forget to give Kudos