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# If each term in the sum A1+A2+...+ An is either 7 or 77 and

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VP
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If each term in the sum A1+A2+...+ An is either 7 or 77 and [#permalink]

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16 Apr 2006, 04:14
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If each term in the sum A1+A2+...+ An is either 7 or 77 and the sum equals 350, which of the following could be equal to n?
VP
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16 Apr 2006, 04:51
n =10

7x + 77y = 350

7(x+11y) = 350

x+11y = 50

x=6 y=4
Senior Manager
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16 Apr 2006, 05:11
[quote="trivikram"]n =10

7x + 77y = 350

7(x+11y) = 350

x+11y = 50

x=6 y=4[/quote]

7 x 6 + 77 x4 = 42 + 308 =350

also

7 x 17 + 77 x 3 = 350

n = 20

what are the options?

7 x 17 + 77 x3 =
VP
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16 Apr 2006, 05:16
old_dream_1976 wrote:
trivikram wrote:
n =10

7x + 77y = 350

7(x+11y) = 350

x+11y = 50

x=6 y=4

7 x 6 + 77 x4 = 42 + 308 =350

also

7 x 17 + 77 x 3 = 350

n = 20

what are the options?

7 x 17 + 77 x3 =

Good catch...There are multiple values

x + 11y =50

17 , 3 as you mentioned is the other set

x= 28 and y =2 So n= 30

x=39 and y= 1 so n=40

Also x=50 and y=0 is also possible

So n=10,20,30,40,50
VP
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Re: [PS] Seven!! [#permalink]

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16 Apr 2006, 07:53
sm176811 wrote:
If each term in the sum A1+A2+...+ An is either 7 or 77 and the sum equals 350, which of the following could be equal to n?

I too get multiple values.. Source of the Q please?
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VP
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Re: [PS] Seven!! [#permalink]

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16 Apr 2006, 08:58
sm176811 wrote:
If each term in the sum A1+A2+...+ An is either 7 or 77 and the sum equals 350, which of the following could be equal to n?

7 = x,
77 = 11x,
350= 50x

350= 50x = 11x+(50-11) x = 11x+ 39x, n = 40
350= 50x = 11 (2) x+ [50-11 (2) x] = 11 (2) x+ 28x, n = 30.

so on...... n is 40
VP
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16 Apr 2006, 09:02
AGreed its 40. I should have said the max value...

The question if from another forum, the OA given is 40. Though I guess teh question could have been framed better.
Director
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Re: [PS] Seven!! [#permalink]

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16 Apr 2006, 10:54
Professor wrote:
sm176811 wrote:
If each term in the sum A1+A2+...+ An is either 7 or 77 and the sum equals 350, which of the following could be equal to n?

7 = x,
77 = 11x,
350= 50x

350= 50x = 11x+(50-11) x = 11x+ 39x, n = 40
350= 50x = 11 (2) x+ [50-11 (2) x] = 11 (2) x+ 28x, n = 30.

so on...... n is 40
you rule Pro))
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Re: [PS] Seven!!   [#permalink] 16 Apr 2006, 10:54
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# If each term in the sum A1+A2+...+ An is either 7 or 77 and

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