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If g(x) = 2x^2 + 17, what is g(12)?

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If g(x) = 2x^2 + 17, what is g(12)?  [#permalink]

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New post 26 May 2017, 12:08
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If g(x) = 2x^2 + 17, what is g(12)?

(A) 12
(B) 17
(C) 100
(D) 288
(E) 305

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Re: If g(x) = 2x^2 + 17, what is g(12)?  [#permalink]

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New post 26 May 2017, 13:32
Since g(x) =\(2x^2\)+ 17

Given x=12 as we are asked the value of g(12)

g(12) = \(2*12^2\)+ 17
= 2*144 + 17
=305(Option E)
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Re: If g(x) = 2x^2 + 17, what is g(12)?  [#permalink]

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New post 01 Jun 2017, 09:47
Kritesh wrote:
If g(x) = 2x^2 + 17, what is g(12)?

(A) 12
(B) 17
(C) 100
(D) 288
(E) 305


We are given that g(x) = 2x^2 + 17 and need to determine g(12).

g(12) = 2(12^2) + 1 = 2(144) + 17 = 288 + 17 = 305

Answer: E
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Re: If g(x) = 2x^2 + 17, what is g(12)?  [#permalink]

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New post 11 Feb 2019, 01:41
Bunuel wrote:
If g(x) = 2x^2 + 17, what is g(12)?

(A) 12
(B) 17
(C) 100
(D) 288
(E) 305



g(x) = 2x^2 + 17

g(x)=12
305
IMO E
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Re: If g(x) = 2x^2 + 17, what is g(12)?  [#permalink]

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New post 17 Feb 2019, 11:44
Kritesh wrote:
If g(x) = 2x^2 + 17, what is g(12)?

(A) 12
(B) 17
(C) 100
(D) 288
(E) 305

In this question, if we multiply 12 by 12, then we get even unit digit. Then, if we multiply this even unit digit by 2, then we still get even unit digit. And finally, if we add 7 (even+odd 7=odd) from 17 then we get odd unit digit.

So, we can cross out the following option easily.
(A) 12
(B) 17
(C) 100
(D) 288
(E) 305
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Re: If g(x) = 2x^2 + 17, what is g(12)?   [#permalink] 17 Feb 2019, 11:44
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