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# If Jack bought a computer for \$1000 more than a generic mode

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Intern
Joined: 10 Jun 2012
Posts: 12

Kudos [?]: 45 [0], given: 66

If Jack bought a computer for \$1000 more than a generic mode [#permalink]

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30 Sep 2012, 22:26
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:53) correct 0% (00:00) wrong based on 7 sessions

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If Jack bought a computer for \$1000 more than a generic model, then the price of that computer would have been 8 times the value of the accompanying bonus wireless router, which is 1/4th the price of the generic model. What is the price of the computer?

Here's what I did:
c = \$1000 + g
c = 8b
b = (1/4) g

Thanks!

Kudos [?]: 45 [0], given: 66

Senior Manager
Joined: 28 Aug 2006
Posts: 303

Kudos [?]: 170 [0], given: 0

Re: If Jack bought a computer for \$1000 more than a generic mode [#permalink]

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30 Sep 2012, 22:45
rainbooow wrote:
If Jack bought a computer for \$1000 more than a generic model, then the price of that computer would have been 8 times the value of the accompanying bonus wireless router, which is 1/4th the price of the generic model. What is the price of the computer?

Here's what I did:
c = \$1000 + g
c = 8b
b = (1/4) g

Thanks!

Continuing your approach and replace b with 1/4g in c= 8b
We get c = 2g
We also have c = 1000 + g
Equating, we get 2g = 1000 + g => g = 1000
Hence, the price of the computer = 2g = \$2000
_________________

Kudos [?]: 170 [0], given: 0

Intern
Joined: 10 Jun 2012
Posts: 12

Kudos [?]: 45 [0], given: 66

Re: If Jack bought a computer for \$1000 more than a generic mode [#permalink]

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30 Sep 2012, 23:13
Сicerone, well done! Thank you for ur quick answer!

Kudos [?]: 45 [0], given: 66

Moderator
Joined: 01 Sep 2010
Posts: 3355

Kudos [?]: 9071 [0], given: 1154

Re: If Jack bought a computer for \$1000 more than a generic mode [#permalink]

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01 Oct 2012, 04:55
c = \$1000 + g is correct C = g + 1000

seems the same but the correct translation is the second one
_________________

Kudos [?]: 9071 [0], given: 1154

Intern
Joined: 10 Jun 2012
Posts: 12

Kudos [?]: 45 [0], given: 66

Re: If Jack bought a computer for \$1000 more than a generic mode [#permalink]

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01 Oct 2012, 05:17
carcass wrote:
c = \$1000 + g is correct C = g + 1000

seems the same but the correct translation is the second one

I like them both

Kudos [?]: 45 [0], given: 66

Re: If Jack bought a computer for \$1000 more than a generic mode   [#permalink] 01 Oct 2012, 05:17
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