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# If k > 0 and m > 0, what is the value of 3(k+m)+4k/(2k + m)?

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Math Expert
Joined: 02 Sep 2009
Posts: 56275
If k > 0 and m > 0, what is the value of 3(k+m)+4k/(2k + m)?  [#permalink]

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07 Aug 2018, 05:24
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35% (medium)

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75% (01:30) correct 25% (01:32) wrong based on 62 sessions

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If k > 0 and m > 0, what is the value of $$\frac{3(k+m)+4k}{2k + m}$$?

(1) k + m = 9

(2) k = 2m

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Joined: 31 Oct 2013
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Concentration: Accounting, Finance
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Re: If k > 0 and m > 0, what is the value of 3(k+m)+4k/(2k + m)?  [#permalink]

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07 Aug 2018, 05:34
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Bunuel wrote:
If k > 0 and m > 0, what is the value of $$\frac{3(k+m)+4k}{2k + m}$$?

(1) k + m = 9

(2) k = 2m

we are looking for value of $$\frac{3(k+m)+4k}{2k + m}$$

Statement 1: k + m = 9. This one won't help as denominator is 2k + m.

Statement 2 : k = 2m . We can substitute the the value k in the term. Don't worry about m as it must on both numerator and denominator. Sufficient.

The best answer is B.
Re: If k > 0 and m > 0, what is the value of 3(k+m)+4k/(2k + m)?   [#permalink] 07 Aug 2018, 05:34
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# If k > 0 and m > 0, what is the value of 3(k+m)+4k/(2k + m)?

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