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# If k^2 = m^2, which of the following must be true?

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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

What does $$k^2 = m^2$$ imply?

Only that |k| = |m|

(A) k = m
Not necessary e.g. k = 5, m = -5

(B) k = −m
Not necessary e.g. k = 5, m = 5

(C) k = |m|
Not necessary e.g. k = -5, m = 5

(D) k = −|m|
Not necessary e.g. k = 5, m = 5

(E) |k| = |m|
Always necessary. Note that absolute values of the two most be equal for the square to be equal. We cannot say anything about their signs though.

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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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k^2=m^2
Taking the non negative square root of both sides of the equation ,
|k| = |m|
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

With Even powers of variables the signs can't be predicted about them

Hence, We can't say anything about the sign of k and m being positive or negative
therefore, Option A, B, C and D are ruled out as all these options are hinting towards specific and known sign of k and/or m

For any sign of k and m, their absolute values must be same because k^2 = m^2, therefore, |k| = |m|

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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.

If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Since k^2=m^2 we have 0=k^2 – m^2 =(k-m)*(k+m). So k=m or k=-m.
So only (A) and only (B) cannot be an answer.
The choice (C) tells us that k should be greater than or equal to 0.
Similarly the choice (D) tells us that k should be less than or equal to 0.
So neither (C) nor (D) cannot be the answer.

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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Attached is a visual that should help.
Attachments

Screen Shot 2016-04-11 at 4.31.20 PM.png [ 80.7 KiB | Viewed 61484 times ]

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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

As squaring hides the sign of a number, k^2 will equal m^2 for every possible positive/negative combination of the two values.

The only statement we can make for sure is therefore (E) |k| = |m|.
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

The question asks us what MUST be true. So, if we can find a case where a statement is not true, we can eliminate that answer choice.

So, for example, one solution to the equation (k² = m²) is k = 1 and m = 1
Now let's check the answer choices.
A. k = m. Test: 1 = 1. Works. Keep A.
B. k = -m. Test: 1 = -1. DOESN'T WORK. ELIMINATE B.
C. k = |m|. Test: 1 = |1|. Works. Keep C.
D. k = - |m|. Test: 1 = -|1|. DOESN'T WORK. ELIMINATE D.
E. |k| = |m|. Test: |1| = |1|. Works. Keep E.

Okay, so the correct answer is A, C or E

Let's try another case. Another solution to the equation (k² = m²) is k = -1 and m = 1
Now let's check the remaining answer choices.
A. k = m. Test: -1 = 1. DOESN'T WORK. ELIMINATE A.
C. k = |m|. Test: -1 = |1|. DOESN'T WORK. ELIMINATE C.
E. |k| = |m|. Test: |-1| = |1|. Works. Keep E.

By the process of elimination, the correct answer is E

Cheers,
Brent
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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|k| = |m| suffice the condition of k^2 = m^2.

so ans: E
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
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Using the rule that $$\sqrt{x^2}=|x|$$, the equation can be changed to:

$$\sqrt{k^2} = \sqrt{m^2} \rightarrow |k| = |m|$$

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Re: If k^2 = m^2, which of the following must be true? [#permalink]
Shiv2016 wrote:
Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.

Do not follow what you mean bu the point is that $$\sqrt{x^2}=|x|$$, so if we take the square root from k^2 = m^2, we'll get |k| = |m|.
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
Bunuel wrote:
Shiv2016 wrote:
Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.

Do not follow what you mean bu the point is that $$\sqrt{x^2}=|x|$$, so if we take the square root from k^2 = m^2, we'll get |k| = |m|.

Hi. Sorry for being not so clear

I meant to say that even powers ^2,^4, etc. always gives positive outcome no matter what the sign of the base is. For example:
(-2)^2= 4
and
(2)^2= 4

So what I inferred is that k^2 and m^2 are positive (no matter what the sign of k and m are). Therefore we can say that |k|=|m|.

Is this good?
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
Shiv2016 wrote:
Bunuel wrote:
Shiv2016 wrote:
Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.

Do not follow what you mean bu the point is that $$\sqrt{x^2}=|x|$$, so if we take the square root from k^2 = m^2, we'll get |k| = |m|.

Hi. Sorry for being not so clear

I meant to say that even powers ^2,^4, etc. always gives positive outcome no matter what the sign of the base is. For example:
(-2)^2= 4
and
(2)^2= 4

So what I inferred is that k^2 and m^2 are positive (no matter what the sign of k and m are). Therefore we can say that |k|=|m|.

Is this good?

Apart from knowing that the even roots and absolute values give non-negative result, we should also deduce that from k^2 = m^2 we can get |k| = |m|. Else, what would you say if one of the options were k^4 = |m|? Here both sides are also non-negative, but can we say from k^2 = m^2 that k^4 = |m| is true? No.
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

If K squared equals an M squared, that means that a K is equal to plus or minus M.

That basically solves the question, because K is not always M;

it's not always minus M; it's not equal to the absolute value of M because K might

be a negative, so negative cannot be something that's positive.

D says that K, which can either be positive or negative, is always equal to

minus of a positive number; well that's not always correct,

and E is the correct one because it says that plus a equals a plus.
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

Given: k^2 = m^2

Asked: Which of the following must be true?

If k^2 = m^2
Taking root on both sides
|k| = |m|

IMO E
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Re: If k^2 = m^2, which of the following must be true? [#permalink]
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

As $$k^2 = m^2$$ which means that one positive equals the other positive i.e.
+ = +

So we have two possibilities to show that '+ = +'
1. Using even powers : $$(+/-)^2 = (+/-)^2$$
2. Using Mods : |k| = |m| (since $$\sqrt{k^2}$$ = |k|

Among the options only E satisfies. Other options involve one or the other variable which can take either positive or negative values. Here we need only positive terms.

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Re: If k^2 = m^2, which of the following must be true? [#permalink]
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

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