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# If K does not equal 0, 1 or -1, is 1/k > 0? 1) 1/k-1

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Manager
Joined: 08 Feb 2006
Posts: 124

Kudos [?]: 12 [0], given: 0

If K does not equal 0, 1 or -1, is 1/k > 0? 1) 1/k-1 [#permalink]

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19 Apr 2006, 21:34
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If K does not equal 0, 1 or -1, is 1/k > 0?

1) 1/k-1 >0

2) 1/k+1 >0

Kudos [?]: 12 [0], given: 0

Manager
Joined: 20 Mar 2005
Posts: 201

Kudos [?]: 16 [1], given: 0

Location: Colombia, South America

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19 Apr 2006, 21:40
1
KUDOS
jlui4477 wrote:
If K does not equal 0, 1 or -1, is 1/k > 0?

1) 1/k-1 >0

2) 1/k+1 >0

I would go with A

from I) k must be bigger than 1, otherwise would be negative

from II) k can be for instance -0.5 and 1/k+1 > 0 holds
also k can be 2 and 1/k+1 > 0 holds, therefore is insufficient

Kudos [?]: 16 [1], given: 0

Director
Joined: 04 Jan 2006
Posts: 922

Kudos [?]: 37 [0], given: 0

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19 Apr 2006, 21:48
E...

assuming you meant 1/(k-1)

and 1/(k+1)

Kudos [?]: 37 [0], given: 0

VP
Joined: 29 Apr 2003
Posts: 1403

Kudos [?]: 30 [0], given: 0

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20 Apr 2006, 06:18
Anothyer one for A...

From A we get 1/(k-1)>0 or k-1>0 or K>1

From B we get -1<k<2!

Hence A survives!

Kudos [?]: 30 [0], given: 0

Senior Manager
Joined: 24 Jan 2006
Posts: 251

Kudos [?]: 5 [0], given: 0

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20 Apr 2006, 12:40
If K does not equal 0, 1 or -1, is 1/k > 0?

1) 1/k-1 >0

2) 1/k+1 >0

is 1/k>0 => is k<0 i.e. is k -ve

from 1) if 1/k-1>0 => k-1<0 => k<1 so we can't say from this

from 2) 1/k+1 >0 => k+1<0 => k is -ve and < -1

Kudos [?]: 5 [0], given: 0

Senior Manager
Joined: 24 Jan 2006
Posts: 251

Kudos [?]: 5 [0], given: 0

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20 Apr 2006, 12:44
OOHHHH !!!!!! BLUNDER ANOTHER BLUNDER !!

I CANNOT REVERT THE SIGN WHEN I INVERT THE FRACTIONS !!

HUH!! MY HABITS

Kudos [?]: 5 [0], given: 0

20 Apr 2006, 12:44
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