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# If k is a positive integer and k2 is divisible by 20 then

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Intern
Joined: 07 Jul 2008
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If k is a positive integer and k2 is divisible by 20 then [#permalink]

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08 Jul 2008, 13:57
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If “k” is a positive integer and “k2 ” is divisible by 20 then the longest positive integer that must divide “k” is:

a) 4
b) 5
c) 10
d) 20
e) 400

Is the answer d) - 20?
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Joined: 28 Dec 2004
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08 Jul 2008, 14:12
is it k^2 or 2*K? if its 2K=20N

then K can be =10N..so C is a possible choice
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08 Jul 2008, 14:44
Lstyle wrote:
If “k” is a positive integer and “k2 ” is divisible by 20 then the longest positive integer that must divide “k” is:

a) 4
b) 5
c) 10
d) 20
e) 400

Is the answer d) - 20?

I think it is K^2. if so, then k is ivisible by 10.
Since 20 includes one 5 and two 2s, it should be 10. for ex: if k^2 = 100, then k is 10, which is divisible by 10 not by 20.
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Re: Longest positive integer   [#permalink] 08 Jul 2008, 14:44
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