Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 28 May 2017, 10:46

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If K is a positive integer, is K the square of an integer?

Author Message
Manager
Joined: 10 Oct 2005
Posts: 113
Location: Hollywood
Followers: 0

Kudos [?]: 73 [0], given: 0

If K is a positive integer, is K the square of an integer? [#permalink]

### Show Tags

28 Jan 2007, 08:41
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If K is a positive integer, is K the square of an integer?

(1) K is divisible by 4
(2) K is divisible by exactly 4 different prime numbers

(A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
(B) Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D) EACH statement ALONE is sufficient.
(E)Statements (1) and (2) TOGETHER are NOT sufficient.
_________________

The GMAT, too tough to be denied.
Beat the tough questions...

SVP
Joined: 01 May 2006
Posts: 1796
Followers: 9

Kudos [?]: 154 [0], given: 0

### Show Tags

28 Jan 2007, 08:50
(B) for me

Stat1

o If K=4, K = 2^2
o If K=8, K= 2^2 * 2

INSUFF.

Stat2
The answer to the original question is no. If K is the product of exactly 4 prime numbers, we can not have an integer i such that K = i^2.

This is due to the definition of a prime : a prime is not divisable by any integer except 1 and itself.

We have ,for example, K = 2*3*5*7. We could never have K = 2^2 * 3^2.

SUFF.
Senior Manager
Joined: 23 Jun 2006
Posts: 387
Followers: 1

Kudos [?]: 322 [0], given: 0

### Show Tags

28 Jan 2007, 09:25
actually, i'd say E is the answer....

certainly st.2 doesn't speak about all factors, but only about prime factors. so the fact that there is 4 different prime factors doesn't rule out the possibility that it is a square. for example 2^2*3^2*5^2*7^2 is a square with exactly 4 different prime factors.
SVP
Joined: 01 May 2006
Posts: 1796
Followers: 9

Kudos [?]: 154 [0], given: 0

### Show Tags

28 Jan 2007, 09:39
(E) it is... yes

I misread the question ... Reading K is the product of 4 primes
28 Jan 2007, 09:39
Display posts from previous: Sort by