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CEO  S
Joined: 20 Mar 2014
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Concentration: Finance, Strategy
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If k is an integer greater than 1, is k equal to 2^r for  [#permalink]

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NoHalfMeasures wrote:
If k is an integer greater than 1, is k equal to 2^r for some positive integer r?

(1) k is divisible by 2^6

(2) k is not divisible by any odd integer greater than 1

Search for a question before you post.

Topics merged.

For your question, the question asks whether k=2^r ?

Per statement 1, k=2^6*p ---> k =3*2^6 or 5*2^6 and you can not express these numbers in the form of 2^r. But if k=2*2^6 or 4*2^4 , then "yes" you can express k = 2^r. Thus this statement gives you 2 different answers for the question asked. Hence not sufficient.

Per statement 2, if k is NOT divisible by any odd integer >1 ---> k can only take the following forms : 2 or 4 or 8 or 16 etc and YES all these forms can be expressed as 2^r. Thus this statement is sufficient to answer the question asked.

Hence B is the correct answer.

Hope this helps.
Current Student D
Joined: 12 Aug 2015
Posts: 2567
Schools: Boston U '20 (M)
GRE 1: Q169 V154 Re: If k is an integer greater than 1, is k equal to 2^r for  [#permalink]

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Superlative Question
here statement 2 is sufficient as x has to have only even prime that is two as its prime factor
hence B
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Data Sufficiency having the word "some" , "few", "could" , etc  [#permalink]

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If k is an integer greater than 1, is k equal to 2^r for some positive integer r? (D)
(1) k is divisible by 2^6
(2) k is not divisible by any odd integer greater than 1

Now here we have the word "some".
Stmnt 1 is true for some values of r = 7,8,etc

So why is it insufficient ?
Math Expert V
Joined: 02 Sep 2009
Posts: 58453
Re: If k is an integer greater than 1, is k equal to 2^r for  [#permalink]

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shahrukh0603 wrote:
If k is an integer greater than 1, is k equal to 2^r for some positive integer r? (D)
(1) k is divisible by 2^6
(2) k is not divisible by any odd integer greater than 1

Now here we have the word "some".
Stmnt 1 is true for some values of r = 7,8,etc

So why is it insufficient ?

Merging topics. Please refer to the discussion on previous pages.

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Intern  Joined: 19 Aug 2015
Posts: 4
Re: If k is an integer greater than 1, is k equal to 2^r for  [#permalink]

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Bunuel wrote:
shahrukh0603 wrote:
If k is an integer greater than 1, is k equal to 2^r for some positive integer r? (D)
(1) k is divisible by 2^6
(2) k is not divisible by any odd integer greater than 1

Now here we have the word "some".
Stmnt 1 is true for some values of r = 7,8,etc

So why is it insufficient ?

Merging topics. Please refer to the discussion on previous pages.

I know it gives you different answers but the question also says "some". Not getting this discrepancy.
Magoosh GMAT Instructor G
Joined: 28 Dec 2011
Posts: 4472
If k is an integer greater than 1, is k equal to 2^r for  [#permalink]

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1
shahrukh0603 wrote:
Bunuel wrote:
shahrukh0603 wrote:
If k is an integer greater than 1, is k equal to 2^r for some positive integer r? (D)
(1) k is divisible by 2^6
(2) k is not divisible by any odd integer greater than 1

Now here we have the word "some".
Stmnt 1 is true for some values of r = 7,8,etc

So why is it insufficient ?

Merging topics. Please refer to the discussion on previous pages.

I know it gives you different answers but the question also says "some". Not getting this discrepancy.

Dear shahrukh0603,
I'm happy to respond. My friend, this is a very specialized use of the word "some," a use quite different from the use in ordinary language, but a use typical of mathematics.

When a problem is specifying a precise mathematical condition, it uses the term "some value" to mean "a unique and in existence but currently unknown value." That is the sense of the word in this problem. You see, not in GMAT math, but in higher mathematics, many many proofs are "existence proofs." For example, if you have taken calculus, the Mean Value Theorem is an existence theorem: it merely guarantees that a particular value, the mean value, exists----it doesn't give us any concrete ideas about how to find that value. With the Mean Value Theorem, it's relatively simple to do the calculation to solve, but with many problem in levels of math far beyond calculus, all we have is the proof of existence: we have no way to know how to find the value whose existence is guaranteed.

This prompt question uses the word "some" in the sense of mathematical existence, not in the ordinary colloquial sense. In other words, it is saying,

If k is an integer greater than 1, does there exist a particular positive integer r, such that k = 2^r?

The problem with Statement #1 is that it gives a maybe answer to this precise question.

If k = 2^8, then r = 8, the unique value exists. Answer = Yes.

If k = 5(2^8), then there is no possible positive integer value of r such that k = 2^r (the value of r would be 8 + ln(5)/ln(2) = 10.32192809..., which is not an integer---you do not need to know how to find that expression or value for the GMAT). Answer = No.

Since both a yes and a no answer are possible, this statement is insufficient.

Does all this make sense?
Mike _________________
Mike McGarry
Magoosh Test Prep

Education is not the filling of a pail, but the lighting of a fire. — William Butler Yeats (1865 – 1939)
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Re: If k is an integer greater than 1, is k equal to 2^r for  [#permalink]

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_________________ Re: If k is an integer greater than 1, is k equal to 2^r for   [#permalink] 01 Oct 2018, 14:57

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