Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

I am getting E. What is the OA.
2K+3m=t
S1: k=3 implies 2K=6 Let m=1 therefore t=9 which is not a multiple of 12
k=3 implies 2K=6 Let m=6 therfore t=24 which is a multiple of 12

St2: k=1 m=3 t=11
k=1 m=6 t=20
k=3 m=6 t=24

Together S1 & St2 does not satisfy as well
_________________

I am getting E. What is the OA. 2K+3m=t S1: k=3 implies 2K=6 Let m=1 therefore t=9 which is not a multiple of 12 k=3 implies 2K=6 Let m=6 therfore t=24 which is a multiple of 12

St2: k=1 m=3 t=11 k=1 m=6 t=20 k=3 m=6 t=24

Together S1 & St2 does not satisfy as well

The question is asking not if t divisible by 12, but if 12 and t have common multiple:

'do t and 12 have a common factor greater than 1 ? ' if t is divisible by either 2,3,4,6, the answer is 'yes'

If k, m, and t are positive integers and \(\frac{k}{6} + \frac{m}{4} = \frac{t}{12}\), do t and 12 have a common factor greater than 1 ? (1) k is a multiple of 3. (2) m is a multiple of 3.
_________________

Trying hard to achieve something unachievable now....

If k, m, and t are positive integers and \(\frac{k}{6} + \frac{m}{4} = \frac{t}{12}\), do t and 12 have a common factor greater than 1 ? (1) k is a multiple of 3. (2) m is a multiple of 3.

(1) k is a multiple of 3 --> \(k=3x\), where \(x\) is a positive integer --> \(2k+3m=6x+3m=3(2x+m)=t\) --> \(t\) is multiple of 3, hence \(t\) and 12 have a common factor of 3>1. Sufficient.

(2) m is a multiple of 3 --> \(m=3y\), where \(y\) is a positive integer --> \(2k+3m=2k+9y=t\) --> \(t\) and 12 may or may not have a common factor greater than 1. Not sufficient.

Re: If k, m, and t are positive integer [#permalink]

Show Tags

26 Oct 2010, 08:03

Given:

k > 0, m > 0, t > 0 and k, m and t are integers && \(\frac{k}{6}\) + \(\frac{m}{4}\) = \(\frac{t}{12}\)

To prove, t and 12 have a common factor greater than 1 ... we have to show that t is multiple of any factor of 12 other than 1. i.e., 2 (or) 3 (or) 4 (or) 6 (or) 12

(1) K is a multiple of 3 ==> k = 3a If we substitute k in (**) then we get ==> 2 * 3a + 3m = t ==> 3 (2a + m) = t ==> clearly t is multiple of 3 and this is enough to answer the question ==> Sufficient

(2) m is a multiple of 3 ==> m = 3a If we substitute m in (**) then we get ==> 2k + 3 * 3a = t ==> 2k + 9a = t ==> Not sufficient

Hence, Ans: A
_________________

Cheers! Ravi

If you like my post, consider giving me some KUDOS !!!

t and 12 have a common factor greater than 1 [#permalink]

Show Tags

05 Mar 2011, 02:57

90) If k,m and t are positive integers and k/6 + m/4 =t/12, do t and 12 have a common factor greater than 1?

1) K is a multiple of 3 2) m is a multiple of 3

Rephrase-- Is t multiple of 2 ---- minimum requirement 2k+3m/12 = t/12

a) k is multiple of 2 nd 3

Sufficient

b) m is multiple of 3 => m is multiple of 9

Pls tell where m i wrong as the question has multiple of two and alone sufficient. Pls rephrase the question.I think i did mistake while rephrasing but when i attempted this question w/o rephrase first time i mark E second time i mark C. Both the times i was wrong.
_________________

The proof of understanding is the ability to explain it.

Re: t and 12 have a common factor greater than 1 [#permalink]

Show Tags

05 Mar 2011, 03:13

If k,m and t are positive integers and k/6 + m/4 =t/12, do t and 12 have a common factor greater than 1?

1) k is a multiple of 3 2) m is a multiple of 3

12 = 2*2*3. Rephrasing the question - Is t a multiple of 2 or 3?

k/6 + m/4 =t/12 Multiply both sides by 12 => 2k + 3m = t

1) Sufficient. k=3 2*3 + 3m = t t is a multiple of 3. The answer is YES

2) Insufficient m=3 2k+3*3 = t

k=1, t=11. The answer is NO k=3, t=15. The answer is YES

GMATD11 wrote:

90) If k,m and t are positive integers and k/6 + m/4 =t/12, do t and 12 have a common factor greater than 1?

1) K is a multiple of 3 2) m is a multiple of 3

Rephrase-- Is t multiple of 2 ---- minimum requirement 2k+3m/12 = t/12

a) k is multiple of 2 nd 3

Sufficient

b) m is multiple of 3 => m is multiple of 9

Pls tell where m i wrong as the question has multiple of two and alone sufficient. Pls rephrase the question.I think i did mistake while rephrasing but when i attempted this question w/o rephrase first time i mark E second time i mark C. Both the times i was wrong.

No worries! Think of DS paraphrase as the CR must be true statement. If you infer too much, you are wrong. You you infer too less, you are wrong. I think there is high correlation between verbal and math sections of gmat - high scores in CR will correlate with high DS caliber basically you are reasoning you way to the answer. Do I sound like a philosopher? Pardon me, this is not the psychology forum.

1 says k is multiple of 3, then just by looking at the above equation one can say t is also multiple of 3. Sufficient 2. m is multiple of 3 . that doesnt help us in any way here, also we dont know anything about k . so insufficient.

We’ve given one of our favorite features a boost! You can now manage your profile photo, or avatar , right on WordPress.com. This avatar, powered by a service...

Sometimes it’s the extra touches that make all the difference; on your website, that’s the photos and video that give your content life. You asked for streamlined access...

Post today is short and sweet for my MBA batchmates! We survived Foundations term, and tomorrow's the start of our Term 1! I'm sharing my pre-MBA notes...

“Keep your head down, and work hard. Don’t attract any attention. You should be grateful to be here.” Why do we keep quiet? Being an immigrant is a constant...