subhen wrote:
I am getting E. What is the OA.
2K+3m=t
S1: k=3 implies 2K=6 Let m=1 therefore t=9 which is not a multiple of 12
k=3 implies 2K=6 Let m=6 therfore t=24 which is a multiple of 12
St2: k=1 m=3 t=11
k=1 m=6 t=20
k=3 m=6 t=24
Together S1 & St2 does not satisfy as well
The question is asking not if t divisible by 12, but if 12 and t have common multiple:
'do t and 12 have a common factor greater than 1 ? ' if t is divisible by either 2,3,4,6, the answer is 'yes'
It is another "twister" Gmat trap =)