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# If k not equal 0, 1, or -1, is 1/k >0 1) 1/(k-1) > 0

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Intern
Joined: 29 Aug 2009
Posts: 11
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Kudos [?]: 1 [0], given: 1

If k not equal 0, 1, or -1, is 1/k >0 1) 1/(k-1) > 0 [#permalink]

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13 Sep 2009, 15:52
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100% (01:47) correct 0% (00:00) wrong based on 1 sessions

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If k not equal 0, 1, or -1, is 1/k >0
1) 1/(k-1) > 0
2) 1/(k+1) > 0
Manager
Joined: 25 Aug 2009
Posts: 175
Followers: 1

Kudos [?]: 91 [0], given: 12

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13 Sep 2009, 16:08
I will go with A.

The question is $$\frac{1}{k} > 0 or , is k > 0?$$

1.) $$\frac{1}{k-1} > 0$$

=> $$k - 1 > 0$$
=> $$k > 1; Sufficient$$

2.) $$\frac{1}{k+1} > 0$$
=> $$k + 1 > 0$$
=>$$k > -1$$... K can be greator than 0 or not, Uncertainity..insufficient..
Intern
Joined: 29 Aug 2009
Posts: 11
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Kudos [?]: 1 [0], given: 1

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13 Sep 2009, 16:14
Yes, answer is A. thanks for explanation.
Re: explanation   [#permalink] 13 Sep 2009, 16:14
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