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# If kmn ≠ 0, is x/m*(m^2 + n^2 + k^2) = xm + yn + zk?

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Intern
Joined: 25 Nov 2013
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Schools: NUS '18
Re: If kmn ≠ 0, is x/m*(m^2 + n^2 + k^2) = xm + yn + zk?  [#permalink]

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25 Jan 2018, 03:12
Bunuel why kmn#0 is given in the question stem ?
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Re: If kmn ≠ 0, is x/m*(m^2 + n^2 + k^2) = xm + yn + zk?  [#permalink]

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25 Jan 2018, 04:37
satishov wrote:
Bunuel why kmn#0 is given in the question stem ?

k, m, and n are in the denominators. Since we cannot divide by 0, then we should rule out this case because otherwise the fractions won't be defined.
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Re: If kmn ≠ 0, is x/m*(m^2 + n^2 + k^2) = xm + yn + zk?  [#permalink]

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02 May 2018, 23:07
Is there any quick method? It took me 4:26 mins to solve as Bunuel suggests above.
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Re: If kmn ≠ 0, is x/m*(m^2 + n^2 + k^2) = xm + yn + zk?  [#permalink]

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03 May 2018, 22:18
Mehemmed wrote:
Is there any quick method? It took me 4:26 mins to solve as Bunuel suggests above.

Hello

This question will work best with algebra only, with manipulating the statements and the question stem given. Apart from Bunuel's solution, you can also look at the following solution posted in this thread:

https://gmatclub.com/forum/if-kmn-0-is- ... l#p1716490
Re: If kmn ≠ 0, is x/m*(m^2 + n^2 + k^2) = xm + yn + zk? &nbs [#permalink] 03 May 2018, 22:18

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