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If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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16 Nov 2012, 03:45
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If lines y=mx+b and x=y+bm intersect at a degrees angle (where a<90 ), what is the value of angle a ? (1) m=2 (2) m=b Source: Jamboree
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Re: If lines y=mx+b [#permalink]
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16 Nov 2012, 03:59
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Marcab wrote: If lines y=mx+b and x=y+bm intersect at a degrees angle (where a<90 ), what is the value of angle a ?
(1) m=2
(2) m=b
Source: Jamboree To find the angle between two lines, we need to know the slope of both lines. But as shown in the figure, this angle "a" can be either "x" or "y". But since we are given that a<90, we can find out which angle is required because x + y = 180. The slope of the second line is obviously 1. So the question is basically asking for the value of m. 1) Sufficient 2) We get y = bx + b. b is still unknown. Insufficient. Answer is hence A. Kudos Please... If my post helped.
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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stne wrote: abhisingla wrote: How do we apply this formula? In this question m1= 2 and m2=1, does that mean angle is \(\frac{21}{1+2.1} = \frac{1}{3}\) is there a \(tan^{1}\)before this, so angle between two lines having slopes m1 and m2 \(= tan^{1}\frac{m1m2}{1+m1m2}\)
In short how do we actually determine the angle between 2 lines given their slopes? Thanks
We do not care about the actual measure of the angle. When we have to determine the angle at which two lines intercept, the ONLY thing we have to know is the slope of each line . With statement 1 we get (note that I consider only the slopes of the two equations): line1: \(y=2x\) line2: \(y=x\) Once we have those, we are able to determine the length of the angles at the point of intersection. Those angles are fixed and do not change, hence we can determine their length, but in this DS we do not care about the actual number. With statement 1, can you answer the question? YES, that's enough.To determine the angle we would have to use formulas that are beyond the scope of the GMAT ("tan" for example) http://planetmath.org/anglebetweentwolinesbut the point here, as I said above, is not to find the measure.
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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05 Mar 2013, 18:25
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Angle between 2 lines is m1m2/1+m1m2 ..
We already know slope of line X = Y + bm.
Option A tells slope of line A  so suffcient but option B tells nothing so not sufficient



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Re: if lines y = mx + b and y = x + bm [#permalink]
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akshaybansal991 wrote: if lines y = mx + b and y = x + bm intersect at A degrees (A<90) what is the value of angle A
1) m = 2 2) m = b This is a DS question Hello akshaybansal1991, Welcome to GC!! You may want refer to below posts for easier navigation on the site and get more out of Gmatclub newtothegmatclubstarthere130870.htmlrulesforpostinginverbalgmatforum134642.html#p1097623rulesforpostingpleasereadthisbeforeposting133935.html#p1092822The Question has been discussed before: iflinesymxbandxybmintersectatadegreesangle142552.html#p1144329Coming back to the question if lines y = mx + b and y = x + bm intersect at A degrees (A<90) what is the value of angle A 1) m = 2 2) m = b We know the slope of lines as 1 and m and thus we need to find only m and we can find the angle between 2 lines. St1 gives you that data and is sufficient St2 gives you nothing about value of m and hence not sufficient. Similar question practice linesintersectinganglesm08q1566826.html#p1235093
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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23 Nov 2012, 06:12
Marcab wrote: If lines y=mx+b and x=y+bm intersect at a degrees angle (where a<90 ), what is the value of angle a ?
(1) m=2
(2) m=b
Source: Jamboree We can find the angle of intersection b/w any 2 lines if we knw the values of their individual slopes. For y = x + bm, slope is 1; for y = mx + b, slope is "m" (1) Tan (a) = (m  1)/(1 + 1*m); tan(a) < 90 if its value is +ve;since m1>0, no need to add/subtract from 180. Since statement 2 gives m=2, it is sufficient. (2) Test y=x+1, y=2x+2 and y=3x+3 with " y=x  1, y=x4, and y=x9" y=x+1 and y=x gives 0 degrees y=2x+2 and y=x4 gives a diffrent value...INSUFF
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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15 Feb 2013, 02:51
Folks, I understand A is sufficient to find the angle.. but how do you find the angle?
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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15 Feb 2013, 03:58
Marcab wrote: m= tan x. So x= tan inverse(m). but m is slope of which line out of the that intersect?
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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20 Feb 2013, 16:07
m is the slope of the line y=mx+b If you draw an equation for this line, you will find m to be the slope of the line and b to be the intersect on y axis(when x=0). This is called the slopeintercept form of line equation and you memorizing it will help you deal with such questions. The form of such lines is y=(slope)x+yintersect The other line x=y+bm can be written in a similar fashion y=xbm. Going by the above stated formula, since the coefficient of x=1, slope =1. The yintersect of the line is bm. Hope that clarifies your doubt. Sachin9 wrote: Marcab wrote: m= tan x. So x= tan inverse(m). but m is slope of which line out of the that intersect?



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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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01 Aug 2013, 00:34
abhisingla wrote: Angle between 2 lines is m1m2/1+m1m2 ..
We already know slope of line X = Y + bm.
Option A tells slope of line A  so suffcient but option B tells nothing so not sufficient How do we apply this formula? In this question m1= 2 and m2=1, does that mean angle is \(\frac{21}{1+2.1} = \frac{1}{3}\) is there a \(tan^{1}\)before this, so angle between two lines having slopes m1 and m2 \(= tan^{1}\frac{m1m2}{1+m1m2}\) In short how do we actually determine the angle between 2 lines given their slopes? Thanks
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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01 Aug 2013, 01:04
Zarrolou wrote: stne wrote: abhisingla wrote: How do we apply this formula? In this question m1= 2 and m2=1, does that mean angle is \(\frac{21}{1+2.1} = \frac{1}{3}\) is there a \(tan^{1}\)before this, so angle between two lines having slopes m1 and m2 \(= tan^{1}\frac{m1m2}{1+m1m2}\)
In short how do we actually determine the angle between 2 lines given their slopes? Thanks
We do not care about the actual measure of the angle. When we have to determine the angle at which two lines intercept, the ONLY thing we have to know is the slope of each line . With statement 1 we get (note that I consider only the slopes of the two equations): line1: \(y=2x\) line2: \(y=x\) Once we have those, we are able to determine the length of the angles at the point of intersection. Those angles are fixed and do not change, hence we can determine their length, but in this DS we do not care about the actual number. With statement 1, can you answer the question? YES, that's enough.To determine the angle we would have to use formulas that are beyond the scope of the GMAT ("tan" for example) http://planetmath.org/anglebetweentwolinesbut the point here, as I said above, is not to find the measure. That definitely helps ! Other solutions involving tan kept me wondering if indeed it was beyond scope or not,+1
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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01 Aug 2013, 01:30
Marcab wrote: If lines y=mx+b and x=y+bm intersect at a degrees angle (where a<90 ), what is the value of angle a ?
(1) m=2
(2) m=b
Source: Jamboree Correct answer is A Since Slope of y=mx+b is m let it be m1 and slope of y=xmb is 1 , let it m2 Now tan(a) = m1m2/(1+m1*m2) ie tan(a) = m1/(1+m*1)= m1/m+1 Hence knowing the value m will give us answer



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if lines y = mx + b and y = x + bm [#permalink]
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17 Jun 2014, 00:02
if lines y = mx + b and y = x + bm intersect at A degrees (A<90) what is the value of angle A 1) m = 2 2) m = b This is a DS question The Question has been discussed before: iflinesymxbandxybmintersectatadegreesangle142552.html#p1144329
Last edited by WoundedTiger on 17 Jun 2014, 00:22, edited 2 times in total.
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Re: If lines y=mx+b and x=y+bm intersect at a degrees angle [#permalink]
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18 Jun 2014, 07:19
Zarrolou wrote: stne wrote: abhisingla wrote: How do we apply this formula? In this question m1= 2 and m2=1, does that mean angle is \(\frac{21}{1+2.1} = \frac{1}{3}\) is there a \(tan^{1}\)before this, so angle between two lines having slopes m1 and m2 \(= tan^{1}\frac{m1m2}{1+m1m2}\)
In short how do we actually determine the angle between 2 lines given their slopes? Thanks
We do not care about the actual measure of the angle. When we have to determine the angle at which two lines intercept, the ONLY thing we have to know is the slope of each line . With statement 1 we get (note that I consider only the slopes of the two equations): line1: \(y=2x\) line2: \(y=x\) Once we have those, we are able to determine the length of the angles at the point of intersection. Those angles are fixed and do not change, hence we can determine their length, but in this DS we do not care about the actual number. With statement 1, can you answer the question? YES, that's enough.To determine the angle we would have to use formulas that are beyond the scope of the GMAT ("tan" for example) http://planetmath.org/anglebetweentwolinesbut the point here, as I said above, is not to find the measure. Agree that Tan and other trignometry concepts are out of the remit of GMAT but is the formula for angle between two lines m1m2/1+m1m2 in scope ? In other words can this question come in PS section ?



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