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If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 09:20
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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 13:48
Answer:
A = Y/200,
Done this by taking numbers:
Let 10 (x) be 5% (m) of 2 * 100 (y)
Then m/x*100 = 5/10*100 = 50% or 1/2
50% or 1/2 in terms of Y = 100/200 = Y/200



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 14:16
Bunuel wrote: Tough and Tricky questions: Sequences. If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x? A. y/200 B. 2y C. 50y D. 50/y E. 5000/y Kudos for a correct solution.I did this problem differently than DaVagabond, using some algebraic manipulation as well as properties of fractions and decimals as percentages. My solution is as follows: For this problem, one needs to know a little about converting to percentages. First, when saying x is m percent of 2y, this means we need to know how to write some number m as a percentage. As percent implies (per one hundred) dividing m by 100 gives us m as a percentage. So we have x is m percent of 2y, or x = (m/100)*2y. This is because when saying x is a certain percentage of another number, you can find x by multiplying the given number by that percentage. The next property we need to know is how to convert a fraction into a percentage. The problem wants us to find out what percentage m is of x. This value will be equal to (m/x)*100. Whenever finding what percentage some number m is of some number x, one can simply divide m/x and then multiply by 100. For example, when finding what percent 2 is of 3, 2/3 as a percentage, is 200/3, or 66.7%. Now that we have our equation and our conversion property, we just need to solve. We need to manipulate x = (m/100)*2y and get a term of (m/x). In doing so we find (m/x) = 50/y. To find (m/x) as a percentage, we just multiply 50/y * 100 which gives us an answer of 5000/y. So the answer is choice E.



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 14:52
I did this by picking number.
2Y = 100 m =20 therefore x=20
20 = 100% of x therefore the answer is 2Y...
Hopefully this approach is the correct one.



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 16:08
nachobioteck wrote: I did this by picking number.
2Y = 100 m =20 therefore x=20
20 = 100% of x therefore the answer is 2Y...
Hopefully this approach is the correct one. I used a similar approach of picking numbers and have the same answer: 2Y Picking numbers that make calculating % simple, I choose Y = 50, thus 2Y = 100 Any value for m (such as m=25), therefore, m/2y = x = 25/100 = 25% And.... to find the solution m/x = 25/25 which is 1 (or 100%). Quickly scanning A through E, I see 2y, which is 2(50) = 100. This matches the value I'm looking for. Final answer: 2y



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 20:28
Answer = E = \(\frac{5000}{y}\) x = m% of 2y \(x = \frac{m}{100} * 2y = \frac{2ym}{100}\) \(m = \frac{50}{y} * x\) \(m = \frac{50*100}{y*100} * x\) \(m = \frac{5000}{y} % of x\) General way: a% of bc = a/100 * bc Percent means divide by 100 is the golden rule
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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 22:13
Answer is E = 5000/y.
My approach was same as explained by PareshGmat



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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10 Nov 2014, 23:57
It may also be good idea to look at the original question that this is copied from, Official Guide GMAT Review 2015 Question#181. If m > 0 and x is m percent of y, then, in terms of m, y is what percent of x? A. 100m B. 1/100m C. 1/m D. 10/m E. 10000/m Discussion here: ifm0andxismpercentofythenintermsofmyis103387.html?fl=similarDabral



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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12 Nov 2014, 04:23



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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12 Nov 2014, 04:35
x= m/100 * 2y m = z/100 * x . You have to find z in terms of y!! From first equation : m= x/2y * 100 Therefore x/2y * 100 = z/100 * x So z = 10000/2y = 5000/y
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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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12 Nov 2014, 04:49
x = m% of 2y = m*2y/100
x= my/50
m=50x/y
in terms of %
m= 50*100/y % of x
m= 5000/y % of x



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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18 Apr 2017, 16:17
Bunuel wrote: Tough and Tricky questions: Sequences. If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x? A. y/200 B. 2y C. 50y D. 50/y E. 5000/y We are given that x is m percent of 2y. Thus: x = (m/100)(2y) We need to determine m as a percentage of x, i.e., (m/x)(100). Let’s simplify our equation: x = (m/100)(2y) x = 2ym/100 100x = 2ym 100/2y = m/x 50/y = m/x Thus, (m/x)(100) = (50/y)(100) = 5000/y Answer: E
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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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19 Apr 2017, 10:40
Here's my approach.
Given: x= m/100 * 2y
Let m = z% of x
m = z/100 * x m = z/100 * m/100 * 2y (substituting the value of x) solving for z, we get: z = 5000/y
Answer: E



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Re: If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is
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