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If M and N are Integers is M>N ?

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If M and N are Integers is M>N ?  [#permalink]

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New post Updated on: 28 Mar 2016, 12:38
4
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

52% (01:44) correct 48% (02:13) wrong based on 135 sessions

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Originally posted by stonecold on 26 Mar 2016, 13:09.
Last edited by stonecold on 28 Mar 2016, 12:38, edited 1 time in total.
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 05:16
Shouldn't OA be E?
put M=3 and N=-3
or M=3 and N=3
These two conditions will satisfy both 1 and 2.
Please correct if i am doing something wrong here.
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 06:38
I think the OA should be E.
Consider the following cases;
case1:

given m<N^2 is M<N

(M=-1,N=-2) , (M=2,N=4) and (M=N=5)

All satisfy the the given condition hence not sufficient

case 2:
Given M ≤ |N|

(M=-2,N=-4) , (M=-2,N=4) and (M=N=0)

They All satisfy the the given condition hence not sufficient

Combining 1 and 2;still not sufficient

Hence E
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 12:39
techiesam wrote:
I think the OA should be E.
Consider the following cases;
case1:

given m<N^2 is M<N

(M=-1,N=-2) , (M=2,N=4) and (M=N=5)

All satisfy the the given condition hence not sufficient

case 2:
Given M ≤ |N|

(M=-2,N=-4) , (M=-2,N=4) and (M=N=0)

They All satisfy the the given condition hence not sufficient

Combining 1 and 2;still not sufficient

Hence E

Hi There was an error in my typing..
Enjoy the updated question..
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 12:40
KbSharma wrote:
Shouldn't OA be E?
put M=3 and N=-3
or M=3 and N=3
These two conditions will satisfy both 1 and 2.
Please correct if i am doing something wrong here.



Hi There was an error in my typing..
Enjoy the updated question..
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 18:53
2
If M and N are Integers is M<N ?

[1] M < N^2
[2]|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you :P
OA is still E
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 19:11
1
KbSharma wrote:
If M and N are Integers is M<N ?

[1] M < N^2
[2]|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you :P
OA is still E


I have edited the Q.. TRY now..
You will get the answer as per OA..


Chiragjordan, Please be more careful in posting new Qs... There have been errors in your Qs and OAs of late.. Unnecessarily wastes a lot of time and effort of others..
thanks
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 20:21
1
chetan2u wrote:
KbSharma wrote:
If M and N are Integers is M<N ?

[1] M < N^2
[2]|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you :P
OA is still E


I have edited the Q.. TRY now..
You will get the answer as per OA..


Chiragjordan, Please be more careful in posting new Qs... There have been errors in your Qs and OAs of late.. Unnecessarily wastes a lot of time and effort of others..
thanks


In the edited question, if we are going to use B only, i.e., [2]|M| ≤ N, we can tell for sure that M will never be > N.
So, isn't OA B now?
Apologies if I am doing something wrong here but I want to learn. :idea:
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 28 Mar 2016, 20:37
1
KbSharma wrote:
chetan2u wrote:
KbSharma wrote:
If M and N are Integers is M<N ?

[1] M < N^2
[2]|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you :P
OA is still E


I have edited the Q.. TRY now..
You will get the answer as per OA..


Chiragjordan, Please be more careful in posting new Qs... There have been errors in your Qs and OAs of late.. Unnecessarily wastes a lot of time and effort of others..
thanks


In the edited question, if we are going to use B only, i.e., [2]|M| ≤ N, we can tell for sure that M will never be > N.
So, isn't OA B now?
Apologies if I am doing something wrong here but I want to learn. :idea:


hi,
the Editing was done by me to make OA as B, but it seems the OA given is C..
I am changing the OA. Let the original member amend it to the exact given by the SOURCE..
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If M and N are Integers is M>N ?  [#permalink]

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New post 29 Mar 2016, 10:49
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 03 May 2016, 13:31
1
stonecold wrote:
If M and N are Integers is M>N ?

[1] M < N^2
[2]|M| ≤ N


1.
- m=1 ; n=-2 -> m<n^2 ; m>n
- m= -2; n--1 -> m>n^2 ; m<n

--> no suff.

2. |m|≤ n -> -n≤ m≤ n -> [1] (-n≤ m) and [2] (m≤ n)

[2] is clearly suff. to answer the question.

-> ans = B
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Re: If M and N are Integers is M>N ?  [#permalink]

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New post 24 Mar 2018, 22:34
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Re: If M and N are Integers is M>N ?   [#permalink] 24 Mar 2018, 22:34
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