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Current Student D
Joined: 12 Aug 2015
Posts: 2571
Schools: Boston U '20 (M)
GRE 1: Q169 V154 If M and N are Integers is M>N ?  [#permalink]

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4 00:00

Difficulty:   65% (hard)

Question Stats: 52% (01:44) correct 48% (02:13) wrong based on 135 sessions

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If M and N are Integers is M>N ?

 M < N^2
|M| ≤ N

_________________

Originally posted by stonecold on 26 Mar 2016, 13:09.
Last edited by stonecold on 28 Mar 2016, 12:38, edited 1 time in total.
Intern  B
Joined: 17 Dec 2015
Posts: 41
Re: If M and N are Integers is M>N ?  [#permalink]

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Shouldn't OA be E?
put M=3 and N=-3
or M=3 and N=3
These two conditions will satisfy both 1 and 2.
Please correct if i am doing something wrong here.
Manager  G
Joined: 01 Jun 2015
Posts: 207
Location: India
Concentration: Strategy, International Business
GMAT 1: 620 Q48 V26 Re: If M and N are Integers is M>N ?  [#permalink]

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I think the OA should be E.
Consider the following cases;
case1:

given m<N^2 is M<N

(M=-1,N=-2) , (M=2,N=4) and (M=N=5)

All satisfy the the given condition hence not sufficient

case 2:
Given M ≤ |N|

(M=-2,N=-4) , (M=-2,N=4) and (M=N=0)

They All satisfy the the given condition hence not sufficient

Combining 1 and 2;still not sufficient

Hence E
Current Student D
Joined: 12 Aug 2015
Posts: 2571
Schools: Boston U '20 (M)
GRE 1: Q169 V154 Re: If M and N are Integers is M>N ?  [#permalink]

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techiesam wrote:
I think the OA should be E.
Consider the following cases;
case1:

given m<N^2 is M<N

(M=-1,N=-2) , (M=2,N=4) and (M=N=5)

All satisfy the the given condition hence not sufficient

case 2:
Given M ≤ |N|

(M=-2,N=-4) , (M=-2,N=4) and (M=N=0)

They All satisfy the the given condition hence not sufficient

Combining 1 and 2;still not sufficient

Hence E

Hi There was an error in my typing..
Enjoy the updated question..
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Current Student D
Joined: 12 Aug 2015
Posts: 2571
Schools: Boston U '20 (M)
GRE 1: Q169 V154 Re: If M and N are Integers is M>N ?  [#permalink]

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KbSharma wrote:
Shouldn't OA be E?
put M=3 and N=-3
or M=3 and N=3
These two conditions will satisfy both 1 and 2.
Please correct if i am doing something wrong here.

Hi There was an error in my typing..
Enjoy the updated question..
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Intern  B
Joined: 17 Dec 2015
Posts: 41
Re: If M and N are Integers is M>N ?  [#permalink]

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2
If M and N are Integers is M<N ?

 M < N^2
|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you OA is still E
Math Expert V
Joined: 02 Aug 2009
Posts: 7958
Re: If M and N are Integers is M>N ?  [#permalink]

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1
KbSharma wrote:
If M and N are Integers is M<N ?

 M < N^2
|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you OA is still E

I have edited the Q.. TRY now..
You will get the answer as per OA..

Chiragjordan, Please be more careful in posting new Qs... There have been errors in your Qs and OAs of late.. Unnecessarily wastes a lot of time and effort of others..
thanks
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Intern  B
Joined: 17 Dec 2015
Posts: 41
Re: If M and N are Integers is M>N ?  [#permalink]

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1
chetan2u wrote:
KbSharma wrote:
If M and N are Integers is M<N ?

 M < N^2
|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you OA is still E

I have edited the Q.. TRY now..
You will get the answer as per OA..

Chiragjordan, Please be more careful in posting new Qs... There have been errors in your Qs and OAs of late.. Unnecessarily wastes a lot of time and effort of others..
thanks

In the edited question, if we are going to use B only, i.e., |M| ≤ N, we can tell for sure that M will never be > N.
So, isn't OA B now?
Apologies if I am doing something wrong here but I want to learn. Math Expert V
Joined: 02 Aug 2009
Posts: 7958
Re: If M and N are Integers is M>N ?  [#permalink]

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1
KbSharma wrote:
chetan2u wrote:
KbSharma wrote:
If M and N are Integers is M<N ?

 M < N^2
|M| ≤ N

Again, if M=-3 and N=3
And M=3 and N=3
Satisfying both conditions.
Hit kudos if I am right and my persistence irritates you OA is still E

I have edited the Q.. TRY now..
You will get the answer as per OA..

Chiragjordan, Please be more careful in posting new Qs... There have been errors in your Qs and OAs of late.. Unnecessarily wastes a lot of time and effort of others..
thanks

In the edited question, if we are going to use B only, i.e., |M| ≤ N, we can tell for sure that M will never be > N.
So, isn't OA B now?
Apologies if I am doing something wrong here but I want to learn. hi,
the Editing was done by me to make OA as B, but it seems the OA given is C..
I am changing the OA. Let the original member amend it to the exact given by the SOURCE..
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Current Student D
Joined: 12 Aug 2015
Posts: 2571
Schools: Boston U '20 (M)
GRE 1: Q169 V154 If M and N are Integers is M>N ?  [#permalink]

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1
Hey chetan2u and KbSharma => the official answer is indeed B
Thank you for pointing it out

Regards
S.C.S.A
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Joined: 18 Sep 2015
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GMAT 1: 610 Q43 V31 GMAT 2: 610 Q47 V27 GMAT 3: 650 Q48 V31 GMAT 4: 700 Q49 V35 WE: Project Management (Health Care)
Re: If M and N are Integers is M>N ?  [#permalink]

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1
stonecold wrote:
If M and N are Integers is M>N ?

 M < N^2
|M| ≤ N

1.
- m=1 ; n=-2 -> m<n^2 ; m>n
- m= -2; n--1 -> m>n^2 ; m<n

--> no suff.

2. |m|≤ n -> -n≤ m≤ n ->  (-n≤ m) and  (m≤ n)

 is clearly suff. to answer the question.

-> ans = B
Non-Human User Joined: 09 Sep 2013
Posts: 13154
Re: If M and N are Integers is M>N ?  [#permalink]

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_________________ Re: If M and N are Integers is M>N ?   [#permalink] 24 Mar 2018, 22:34
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