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If m is an integer, is m odd? (1) m/2 is not an even integer. (2) m – 3 is an even integer.
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27 Mar 2012, 06:54
dzodzo85 wrote: If m is an integer, is m odd?
(1) m/2 is not an even integer. (2) m – 3 is an even integer.
Please explain this question further can some body please explain to me why A is INSUFFICIENT i see it this way given that select those items which make m/2 <> even so take m = 6, 10, 10, 14 etc they give 3,5,5,7 etc... so m is even , so is m odd is answered in NEGATIVE.....so this is sufficient to answer the question right? can some please explain why it is INSUFFICIENT
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27 Mar 2012, 06:58
harshavmrg wrote: dzodzo85 wrote: If m is an integer, is m odd?
(1) m/2 is not an even integer. (2) m – 3 is an even integer.
Please explain this question further can some body please explain to me why A is INSUFFICIENT i see it this way given that select those items which make m/2 <> even so take m = 6, 10, 10, 14 etc they give 3,5,5,7 etc... so m is even , so is m odd is answered in NEGATIVE.....so this is sufficient to answer the question right? can some please explain why it is INSUFFICIENT Please read the solution above: For m/2 not to be an even integer m can be even (10) as well as odd (5).
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Re: If m is an integer, is m odd? [#permalink]
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31 Mar 2012, 06:18
Bunuel wrote: If m is an integer, is m odd?
(1) m/2 is not an even integer > \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) > \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.
(2) m3 is an even integer > \(modd=even\) > \(m=even+odd=odd\). Sufficient.
Answer: B. Isn't \(\frac{m}{2}\) said to be an integer (though not even)? So that \(\frac{5}{2}\) is not the case. Posted from GMAT ToolKit



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Rigorous wrote: Bunuel wrote: If m is an integer, is m odd?
(1) m/2 is not an even integer > \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) > \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.
(2) m3 is an even integer > \(modd=even\) > \(m=even+odd=odd\). Sufficient.
Answer: B. Isn't \(\frac{m}{2}\) said to be an integer (though not even)? So that \(\frac{5}{2}\) is not the case. Posted from GMAT ToolKitNot so. (1) just says that m/2 is not an even integer, from which you can no way assume that m/2 is an odd integer, it can not be an integer at all.
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If M is an integer, is m odd? [#permalink]
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02 Feb 2013, 11:31
(1) m/2 is not an even integer
(2) m3 is an even integer
I was a bit confused about what statement 1 even meant to be honest. The correct answer is B (only state 2 being sufficient). Can someone help me understand what statement 1 is saying... as well as why it is insufficient? Thanks!



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Re: If M is an integer, is m odd? [#permalink]
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02 Feb 2013, 12:12
Hi there, m/2 is not an even integer This means that if you divide the variable m (which represents some number) that the result will not be an even (a number divisible by 2) integer (a whole number: 1,2,0,1,2...). So M cannot be the number 4 because 4/2 =2 which is an even integer. m could be 5 because 5/2 = 2.5 which is not an integer nor is it even. M could be 6 because 6/2 =3 which is an integer but is not even. So the main point of this statement is that there are two possibilities for m: m is either an even number with only ONE 2 as a factor (2, 6, 14...) or m is odd. Therefore the statement is insufficient because m could be an even number or an odd number.I hope this helps. Let me know if you need any more advise on this. HG.
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ahatoval wrote: Hey guys,
Can anybody explain me why the following is B?
If m is an integer, is m odd?
(1) m/2 is NOT an even integer (2) m  3 is an even integer.
My thought process was:
(1) Since m/2 is NOT an even integer, then => it IS an odd integer. subsequently ODD * 2 = EVEN. Sufficient
Many thanks, Hi ahatoval, this is a common mistake the GMAT likes to exploit, so it's good to have a complete understanding of it. The key is keeping track of what must be an integer, and what doesn't have to be. Statement 2 is correct because m has to be an integer, so any odd integer 3 (or 5 or 7) would be even. Sufficient. You seem to be more concerned with statement 1. This statement tells us that m is an integer, but that m/2 is not an even integer. This is not the same thing as being an odd integer. Let's look at values of m/2 for different m's m=1 ) m/2 = 0.5 m=2 ) m/2 = 1 m=3 ) m/2 = 1.5 m=4 ) m/2 = 2 ... pattern repeats Therefore, if m/2 is not an even integer, then m=4 is excluded from the list of possibilities. This leaves m=1, m=2 and m=3. M/2 can therefore be an odd integer or a noninteger. Since we have examples of both, we cannot conclude with certainty whether m is an odd integer, it can be either 1 or 2 or 3 (or 5 or 6 or 7...) The assumption you make that leads you down the rabbit hole on this question is that m/2 must be an integer. This is not stated in the question and easily demonstrated to be false with a few small examples. On Data Sufficiency, it's often a good idea to try a few numbers and see if you can discern a pattern. Hope this helps! Ron
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Re: If M is an integer, is m odd? [#permalink]
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07 May 2013, 09:18
exploringm wrote: (1) m/2 is not an even integer
(2) m3 is an even integer
I was a bit confused about what statement 1 even meant to be honest. The correct answer is B (only state 2 being sufficient). Can someone help me understand what statement 1 is saying... as well as why it is insufficient? Thanks! in my opinion,m/2 is not an even integer means that m/2 could be an odd integer,but also can not be an integer at all, e.g. a decimal



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Re: If m is an integer, is m odd? [#permalink]
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13 Nov 2013, 17:07
Bunuel wrote: If m is an integer, is m odd?
(1) m/2 is not an even integer > \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) > \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.
(2) m3 is an even integer > \(modd=even\) > \(m=even+odd=odd\). Sufficient.
Answer: B. Banuel, Statement 2 Threw me off When I read it. M3= Even. This is a true statement to the GMAT correct, so does this mean that I now start testing for M. Would it be better to test odd #'s first, then move to even numbers? Such as M=3,5,7,9,



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Re: If m is an integer, is m odd? [#permalink]
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14 Nov 2013, 01:42
selfishmofo wrote: Bunuel wrote: If m is an integer, is m odd?
(1) m/2 is not an even integer > \(\frac{m}{2}\neq{even}\) could occur when \(m\) is odd as well as when \(m\) is even (10 and 5 for example) > \(\frac{m}{2}=\frac{10}{2}=5\neq{even}\) and \(\frac{m}{2}=\frac{5}{2}=2.5\neq{even}\). Not sufficient.
(2) m3 is an even integer > \(modd=even\) > \(m=even+odd=odd\). Sufficient.
Answer: B. Banuel, Statement 2 Threw me off When I read it. M3= Even. This is a true statement to the GMAT correct, so does this mean that I now start testing for M. Would it be better to test odd #'s first, then move to even numbers? Such as M=3,5,7,9, \(modd=even\) means that m is odd: \(m=even+odd=odd\). So, you have an YES answer to the question and don't need to test any numbers at all.
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If m is an integer, is m odd? [#permalink]
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10 Jan 2014, 05:44
This is a question from OG 12th edition If m is an integer, is m odd? 1. (m/2) is not an even integer 2. m  3 is an even integer The answer is B. This is how the explanation is: 1. Since m could be either the odd integer 3 or the even integer 10 and still satisfy this condition, there is no information to show definitively whether m is odd or even; NOT sufficient 2. If m3 is an even integer, then m3 = 2k for some integer k m = 2k +3 = 2(k+1) + 1, which is odd; Sufficient. My question, I understand why 2 is sufficient. When I look at 1, it states that (m/2) is not an even integer. I said if (m/2) is not even then it is odd then: (m/2) could be (1, 3, 5, 7, 9, 11, etc) then: m would be (2, 6, 10, 14, 18, 22, etc). This would mean that m has to be even which is sufficient to answer the question. Can somebody explain why the way I approached it was wrong? Thank You



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Re: If m is an integer, is m odd? [#permalink]
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10 Jan 2014, 06:39
aelayat2 wrote: This is a question from OG 12th edition If m is an integer, is m odd? 1. (m/2) is not an even integer 2. m  3 is an even integer The answer is B. This is how the explanation is: 1. Since m could be either the odd integer 3 or the even integer 10 and still satisfy this condition, there is no information to show definitively whether m is odd or even; NOT sufficient 2. If m3 is an even integer, then m3 = 2k for some integer k m = 2k +3 = 2(k+1) + 1, which is odd; Sufficient. My question, I understand why 2 is sufficient. When I look at 1, it states that (m/2) is not an even integer. I said if (m/2) is not even then it is odd then: (m/2) could be (1, 3, 5, 7, 9, 11, etc) then: m would be (2, 6, 10, 14, 18, 22, etc). This would mean that m has to be even which is sufficient to answer the question. Can somebody explain why the way I approached it was wrong? Thank You Merging similar topics. Please refer to the solutions above. As for your doubt please check here: ifmisanintegerismodd129702.html#p1067835Hope it helps.
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Re: If m is an integer, is m odd? [#permalink]
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24 May 2014, 21:55
1) M/2 is not an even integer
Odd / Even = Not an integer Even / Even = Odd, Even or not an integer
Not sufficient can be odd or even
2) M  3 is an even integer
Odd  Odd = Even Even  Odd = Odd
Must be Odd for m  3 to be an even integer. Sufficient



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If m is an integer, is m odd? [#permalink]
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Not wanting to find excuses, but I do think that statement 1 is wrongly phrased. Epsecially since the gmat is quite strict in verbal, when it comes to meaning! So, for me, "m is not an even integer" means that it is an integer that is not even. Otherwise, it should have been: m is not even. Then it can be whatever  integer or not  as long as it is not even. Then, the question stem would make sense: The stem says " If m is an integer, is m odd?", which means: in the case than m is an integer, is it odd? So, it leaves some space on m being an integer or not. Reading [1], you actually read "m is an integer that is not odd", because "not an even" describes the word integer. So, the adjective "even" describes the word "integer". "Not even" is also used as an adjective, and it still describes the word "integer". This does not leave any space for confusion: m should be an integer. If a verbal genius is around perhaps he/she could refute this argument! Haha!



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02 Mar 2015, 04:11
An additional question.
When you have fractions, can you still refer to them as even and odd? I thought that the words even and odd could only refer to integers.
So, when a number is odd, it is an integer. The same with even.
So, 3 and 2.5 are both odd numbers, while 3 is an odd integer and 2.5 just an odd number?
2.4, in the same logic, is an even number?



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Re: If m is an integer, is m odd? [#permalink]
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pacifist85 wrote: Not wanting to find excuses, but I do think that statement 1 is wrongly phrased. Epsecially since the gmat is quite strict in verbal, when it comes to meaning! So, for me, "m is not an even integer" means that it is an integer that is not even. Otherwise, it should have been: m is not even. Then it can be whatever  integer or not  as long as it is not even. Then, the question stem would make sense: The stem says " If m is an integer, is m odd?", which means: in the case than m is an integer, is it odd? So, it leaves some space on m being an integer or not. Reading [1], you actually read "m is an integer that is not odd", because "not an even" describes the word integer. So, the adjective "even" describes the word "integer". "Not even" is also used as an adjective, and it still describes the word "integer". This does not leave any space for confusion: m should be an integer. If a verbal genius is around perhaps he/she could refute this argument! Haha! I agree with Natalia! The wording of statement 1 is confusing. One could think that m is an integer but not even ==> m is an odd integer. Is it correct wording? By the way there are some guys who do not care about correct wording. How come should i guess that x^2y is not x to the power of 2y but x(^2)y??? Moderators please pay attention to this=))
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Re: If m is an integer, is m odd? [#permalink]
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02 Mar 2015, 05:11
pacifist85 wrote: Not wanting to find excuses, but I do think that statement 1 is wrongly phrased. Epsecially since the gmat is quite strict in verbal, when it comes to meaning! So, for me, "m is not an even integer" means that it is an integer that is not even. Otherwise, it should have been: m is not even. Then it can be whatever  integer or not  as long as it is not even. Then, the question stem would make sense: The stem says " If m is an integer, is m odd?", which means: in the case than m is an integer, is it odd? So, it leaves some space on m being an integer or not. Reading [1], you actually read "m is an integer that is not odd", because "not an even" describes the word integer. So, the adjective "even" describes the word "integer". "Not even" is also used as an adjective, and it still describes the word "integer". This does not leave any space for confusion: m should be an integer. If a verbal genius is around perhaps he/she could refute this argument! Haha! First of all this is OG question, so it's as good as it gets. Next, only integers can be odd or even. So, there is no difference in saying x is even and x is an even integer.
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Re: If m is an integer, is m odd? [#permalink]
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Konstantin1983 wrote: pacifist85 wrote: Not wanting to find excuses, but I do think that statement 1 is wrongly phrased. Epsecially since the gmat is quite strict in verbal, when it comes to meaning! So, for me, "m is not an even integer" means that it is an integer that is not even. Otherwise, it should have been: m is not even. Then it can be whatever  integer or not  as long as it is not even. Then, the question stem would make sense: The stem says " If m is an integer, is m odd?", which means: in the case than m is an integer, is it odd? So, it leaves some space on m being an integer or not. Reading [1], you actually read "m is an integer that is not odd", because "not an even" describes the word integer. So, the adjective "even" describes the word "integer". "Not even" is also used as an adjective, and it still describes the word "integer". This does not leave any space for confusion: m should be an integer. If a verbal genius is around perhaps he/she could refute this argument! Haha! I agree with Natalia! The wording of statement 1 is confusing. One could think that m is an integer but not even ==> m is an odd integer. Is it correct wording? By the way there are some guys who do not care about correct wording. How come should i guess that x^2y is not x to the power of 2y but x(^2)y??? Moderators please pay attention to this=)) x^2y means x^2*y ONLY. If it were x to the power of 2y, then it would be written as x^(2y).
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