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# If m is an integer, is m odd?

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Senior Manager
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If m is an integer, is m odd? [#permalink]

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06 Nov 2005, 13:00
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If m is an integer, is m odd?

(1) m/2 is not an even integer
(2) m-3 is an even integer

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-m-is-an-integer-is-m-odd-129702.html
[Reveal] Spoiler: OA

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06 Nov 2005, 13:10
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it should be B.

if m/2 is not an even integer then m can be an dd integer or a non integer.
so A is not the answer

form statement 2 m-3 is even so m must be odd.
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07 Nov 2005, 20:53
Thats correct Nakib. Good catch, I missed to consider that m/2 could be a fraction and considered only even integers of m and choose D.

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07 Nov 2005, 22:38
Also, picking either 10 or 11 result in a non-even interger for A.

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31 Jul 2006, 15:22
B

St1: m could be anything except a multiple of 4. Like m = 3, m = 6: INSUFF

St2: m is an odd integer: SUFF
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31 Jul 2006, 15:48
(B)

I. says that m/2 can be an odd integer or even a fraction .. Insufficient
II. sufficient.

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31 Jul 2006, 16:34
sgrover wrote:
(B)

I. says that m/2 can be an odd integer or even a fraction .. Insufficient
II. sufficient.

a fraction? but (1) say not AN EVEN INTEGER... so we can't assume that it is ODD Integer?

so 1 to me says m is integer AND m is NOT even integer... so M could be 2 or 6 or 10... it can't be 20 because it would contradict st (1) that says outcome isn't even... which makes M even still confused...

The anwer is B, of course.

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31 Jul 2006, 17:46
yes, the naswer is (B), of course. Here is how I would explain it.

ST1. m is an integer and m/2 is not an even integer

If m=2 then m/2=1 is not an even integer (Note m is even)
If m=3 then m/2=1.5 is not an even integer (Note m is odd here)

So, not sufficient

ST2. Obviously sufficient, m must be odd

(B)

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31 Jul 2006, 18:55
I guess the answer to my question is that if GMAT says if M isn't an even integer, it can be odd interger, a fraction or some other crazy thing

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31 Jul 2006, 20:24
u2lover wrote:
if m is an integer, is m odd?

(1) m/2 is not an even integer
(2) m-3 is an even integer

is (1) saying that m isn't an integer, or it isn't an even integer, or it isn't integer at all

u2 baby, it is clearly said in the question that m is an integer. but we donot know whether it is even or odd. if it is even, m/2 is an odd integer. if it is odd, m/2 is a fraction. so m is a multiple of odd integers. but be sure that m cannot be 0 or multiples of 4.

st 2- its crystal clear.

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31 Jul 2006, 21:11
I know B is crystal clear... but (1) wasn't so crystal (along with the fact that M is an integer) when I tried to solve it

sorry for the stupid questions, I really don't like DS number properties if you can't tell...

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31 Jul 2006, 21:50
I agree with U2lover.

IMO we make these stupid errors because of overconfidence and tryign to solve something fast.

Of course reading (1) its easy to assume that m/2 is an odd integer. But the fact remains that m/2 is not even integer. It can be a fraction hence cannot say anything about m

(2) O - E = E
Hence Suff

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22 Oct 2006, 22:29
Priya,
m/2 is not an even integer can mean that m/2 is not even and/or m/2 is not an integer.

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23 Oct 2006, 05:10
m/2 is NOT an even integer does not necessarily mean that "m/2 is an odd integer" ..........m/2 may not be an integer at all

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23 Oct 2006, 11:04
If m is an integer, is m odd?
1) m/2 is NOT an even integer
2) m-3 is an even integer.

from one

m/2 not even intiger

m could be a fraction or odd ......not suff

from two

m-3 = even only odd-odd = even thus m is even ....suff

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20 Jan 2007, 18:31
If m is an integer, is m odd?
1) m/2 is not an even integer
2) m-3 is an even integer

st one to me means :

m/2 could be odd ie 6/2 = 3 or could be a fraction 1/2 and m might be odd

3/2...........insuff

from two

m is sure odd ......suff B is my answer

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20 Jan 2007, 18:45
I agree, 1 is insufficient, could be even or odd. However any even number subtracted by 3 will be odd everytime.

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20 Jan 2007, 19:58
(1)
yezz wrote:
m/2 could be odd

Exactly. m/2 could be 1/2 (fraction), 2/2 (odd), 3/2(fraction), 4/2 (even)... => (1) insuff => B, C, or E.

(2) is straightfwd. m-3 = even => m = odd, always => B.

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21 Jan 2007, 05:57
Thanks guys. When m/2 is not an even integer, I understood it to be an odd integer. But it could be a fraction too.

m could be odd integer 3 or even integer 10 and satisfy the condition. That is what OE says.

OA B

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21 Jan 2007, 10:39
i'm thinking B

statement 2 shows quite clearly that m is an odd integer

For stat 1, m/2 is not an even integer, i'd interpret it as

m/2 is either an odd integer or m/2 is not an integer at all

so m/2 can be 7 or 49/2 so m can be even or odd

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21 Jan 2007, 10:39

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