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# If m, n and p are constants and x^2 + mx + n = (x + p)^2 for all value

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Math Expert
Joined: 02 Sep 2009
Posts: 58431
If m, n and p are constants and x^2 + mx + n = (x + p)^2 for all value  [#permalink]

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01 Nov 2018, 00:09
00:00

Difficulty:

55% (hard)

Question Stats:

57% (01:34) correct 43% (01:53) wrong based on 32 sessions

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If m, n and p are constants and x^2 + mx + n = (x + p)^2 for all values of x, what is the value of n?

(1) p = 3
(2) m = 6

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Re: If m, n and p are constants and x^2 + mx + n = (x + p)^2 for all value  [#permalink]

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01 Nov 2018, 01:32
Bunuel wrote:
If m, n and p are constants and x^2 + mx + n = (x + p)^2 for all values of x, what is the value of n?

(1) p = 3
(2) m = 6

Question: n = ?

Given: $$x^2 + mx + n = (x + p)^2$$
i.e. $$x^2 + mx + n = x^2 + 2px + p^2$$
i,e, $$m = 2p$$ and $$n = p^2$$

Question REPHRASED: n = ? or p = ? or m = ?

Statement 1: p = 3

SUFFICIENT

Statement 2: m = 6

SUFFICIENT

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Re: If m, n and p are constants and x^2 + mx + n = (x + p)^2 for all value   [#permalink] 01 Nov 2018, 01:32
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