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Intern  S
Joined: 24 Nov 2018
Posts: 19
Location: India
If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3  [#permalink]

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Difficulty:   35% (medium)

Question Stats: 71% (01:35) correct 29% (01:43) wrong based on 34 sessions

### HideShow timer Statistics If m = z^5, is m < 1?

(1) 3 – (y– x) > x– (y– 3z)

(2) z < 3
Intern  B
Joined: 15 Dec 2018
Posts: 29
Location: India
Schools: IIMA PGPX"20
GMAT 1: 650 Q45 V35 GMAT 2: 650 Q45 V45 GPA: 3.5
Re: If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3  [#permalink]

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A

Solving the first equation gives Z<1

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Manager  G
Joined: 10 Oct 2018
Posts: 182
GPA: 4
Re: If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3  [#permalink]

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If m = z^5, is m < 1?

(1) 3 – (y– x) > x– (y– 3z)

(2) z < 3

We are asked to find m<1. For m to be <1, z has to be negative or zero. This is the hidden hint.

Statement 1: 3 – (y– x) > x– (y– 3z) => 3-y+x>x-y+3 after solving will give z<1.
Well, this statement is sufficient as z can be 0 or negative. SUFFICIENT

Statement 2: z < 3 => z can be negative, zero, 1, 2 NOT SUFFICIENT

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Senior Manager  P
Joined: 13 Jan 2018
Posts: 335
Location: India
Concentration: Operations, General Management
GMAT 1: 580 Q47 V23 GMAT 2: 640 Q49 V27 GPA: 4
WE: Consulting (Consulting)
Re: If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3  [#permalink]

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Statement 1)

3 - y + x > x - y + 3z
3 > 3z
1 > z

Z < 1

If Z < 1, then $$Z^5$$ will definitely be less than 1. So m < 1. SUFFICIENT

Statement 2) Z < 3

If Z = 2, then m > 1
If Z = -1 then m < 1

INSUFFICIENT

OPTION: A
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Chaitanya

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Senior Manager  P
Joined: 15 Feb 2018
Posts: 258
Re: If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3  [#permalink]

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What is the source for this question?
VP  G
Joined: 09 Mar 2018
Posts: 1002
Location: India
Re: If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3  [#permalink]

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If m = z^5, is m < 1?

(1) 3 – (y– x) > x– (y– 3z)

(2) z < 3

So from if statement we can say that z can be -ive or +ive

for statement 1) 3 – (y– x) > x– (y– 3z)

to be true in RHS the bold part has to be +ive and less than LHS

y =2 x =1 or y =6, x =2

3 - 1 > 1 - (2- 3*z), so for this statement to be true z has to be less than 1, like 0 or 1/3
2 > -1 or 2 > 0, this answers the question is m < 1 as yes.

Now lets try with y =6, x =2
3 - 4 > 2 - (6 - 3z), so for this statement to be true z has to be less than 1, like 0 or 1/3
-1 > -4 or -1> -3, this again answers the question is m < 1 as yes.

A is sufficient

B) we can get a Yes and a No from this.

A
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Quote which i can relate to.
Many of life's failures happen with people who do not realize how close they were to success when they gave up. Re: If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3   [#permalink] 01 Feb 2019, 23:17
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# If m = z^5, is m < 1? (1) 3 – (y– x) > x– (y– 3z) (2) z < 3  