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If mn≠0, m/r=?

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Math Revolution GMAT Instructor
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If mn≠0, m/r=?  [#permalink]

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New post Updated on: 06 Jul 2017, 10:42
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A
B
C
D
E

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  5% (low)

Question Stats:

89% (00:47) correct 11% (00:57) wrong based on 58 sessions

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If \(mr≠0, \frac{m}{r}\)=?

1) \(\frac{(m+r)}{r}=3\)
2) \(\frac{r}{(m+r)}=\frac{1}{3}\)

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Originally posted by MathRevolution on 06 Jul 2017, 01:21.
Last edited by MathRevolution on 06 Jul 2017, 10:42, edited 1 time in total.
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Re: If mn≠0, m/r=?  [#permalink]

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New post 06 Jul 2017, 02:45
1
Statement 1: (m+r)/r can be re-written as (m/r + r/r) = 3, so m/r +1 = 3, hence, m/r = 2. This statement is SUFFICIENT.

Statement 2: Cross multiply or take a reciprocal and you'll get 3r = 1(m+r), or 2r = m, so m/r = 2. This statement is Sufficient too.

Answer: D
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Re: If mn≠0, m/r=?  [#permalink]

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New post 06 Jul 2017, 04:36
1
MathRevolution wrote:
If \(mn≠0, \frac{m}{r}\)=?

1) \(\frac{(m+r)}{r}=3\)
2) \(\frac{r}{(m+r)}=\frac{1}{3}\)


We need to find the value of \(\frac{m}{r}\)

1) \(\frac{(m+r)}{r}= 3\)

\(\frac{m}{r} + \frac{r}{r}= 3\)

\(\frac{m}{r} + 1 = 3\)

\(\frac{m}{r} = 3 - 1\)

\(\frac{m}{r} = 2\)

Hence I is Sufficient.

2) \(\frac{r}{(m+r)}=\frac{1}{3}\)

\(3r = m+r\)

\(3r - r = m\)

\(2r = m\)

\(\frac{m}{r} = 2\)

Hence II is Sufficient.

Answer (D)...

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Re: If mn≠0, m/r=?  [#permalink]

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New post 09 Jul 2017, 18:23
==> In the original condition, there are 2 variables (m,r) and in order to match the number of variables to the number of equations, there must be 2 equations. Since there is 1 for con 1) and 1 for con 2), C is most likely to be the answer. By solving con 1) and con 2), you get con 1) = con 2), so from m/r+1=3, you get m/r=2, hence it is unique and sufficient.

Therefore, the answer is D.
Answer: D
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Re: If mn≠0, m/r=?   [#permalink] 09 Jul 2017, 18:23
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If mn≠0, m/r=?

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