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# If n > 4, which of the following is equivalent to (n - 4n^(1/2) + 4)/

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Math Expert
Joined: 02 Sep 2009
Posts: 58381
If n > 4, which of the following is equivalent to (n - 4n^(1/2) + 4)/  [#permalink]

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14 Jan 2019, 02:18
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15% (low)

Question Stats:

90% (01:42) correct 10% (01:58) wrong based on 30 sessions

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If n > 4, which of the following is equivalent to $$\frac{n-4\sqrt{n}+4}{\sqrt{n}-2}$$ ?

A. $$\sqrt{n}$$

B. $$2\sqrt{n}$$

C. $$\sqrt{n}+2$$

D. $$\sqrt{n}-2$$

E. $$n+\sqrt{n}$$

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Re: If n > 4, which of the following is equivalent to (n - 4n^(1/2) + 4)/  [#permalink]

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14 Jan 2019, 03:18
Bunuel wrote:
If n > 4, which of the following is equivalent to $$\frac{n-4\sqrt{n}+4}{\sqrt{n}-2}$$ ?

A. $$\sqrt{n}$$

B. $$2\sqrt{n}$$

C. $$\sqrt{n}+2$$

D. $$\sqrt{n}-2$$

E. $$n+\sqrt{n}$$

substitute value of n = 9

we would get 1

IMO D
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If n > 4, which of the following is equivalent to (n - 4n^(1/2) + 4)/  [#permalink]

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14 Jan 2019, 03:51
2
Bunuel wrote:
If n > 4, which of the following is equivalent to $$\frac{n-4\sqrt{n}+4}{\sqrt{n}-2}$$ ?

A. $$\sqrt{n}$$

B. $$2\sqrt{n}$$

C. $$\sqrt{n}+2$$

D. $$\sqrt{n}-2$$

E. $$n+\sqrt{n}$$

$$\frac{n-4\sqrt{n}+4}{\sqrt{n}-2}$$

=$$\frac{(\sqrt{n})^2-2.2\sqrt{n}+2^2}{\sqrt{n}-2}$$

=$$(\sqrt{n} - 2)^2 / \sqrt{n} - 2$$

=$$\sqrt{n} - 2$$

D is the correct answer.
If n > 4, which of the following is equivalent to (n - 4n^(1/2) + 4)/   [#permalink] 14 Jan 2019, 03:51
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# If n > 4, which of the following is equivalent to (n - 4n^(1/2) + 4)/

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