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if n and y are positive integers and n represents the number of different positive factors of y, is y a perfect square?

1) square(n) is odd number

2) y=square(5^(2(n-1))

I think 'square' means 'square-root'. Considering it true, my explanation

\sqrt{n} is an odd number => n would also be an odd number => Sufficient to determine, Y would not have 'even number of factors' and that means it can't a perfect square.

y = \sqrt{5^(2(n-1))} => y= 5^(n-1) => if n is odd than (n-1) would be a perfect square but if n is even, y would not be perfect answer. => NOT Sufficient

if n and y are positive integers and n represents the number of different positive factors of y, is y a perfect square?

1) square(n) is odd number

2) y=square(5^(2(n-1))

I think 'square' means 'square-root'. Considering it true, my explanation

\sqrt{n} is an odd number => n would also be an odd number => Sufficient to determine, Y would not have 'even number of factors' and that means it can't a perfect square.

y = \sqrt{5^(2(n-1))} => y= 5^(n-1) => if n is odd than (n-1) would be a perfect square but if n is even, y would not be perfect answer. => NOT Sufficient

So answer is A

For (1) my understanding is different. A perfect square must have event exponents on it's prime factorization, but an odd number of factors. So like you said, root n is odd, meaning Y has an odd number of factors. If a number has an odd number of factors it is a perfect square.

if n and y are positive integers and n represents the number of different positive factors of y, is y a perfect square?

1) \(\sqrt{n}\) is an odd number.

2) \(y=\sqrt{5^{2(n-1)}}\)

The question is based on the following concept: If a number has odd number of factors, it must be a perfect square. If a number has even number of factors, it cannot be a perfect square. For why and how, check: http://www.veritasprep.com/blog/2010/12 ... t-squares/

n is the number of positive factors of y. Question: Is y a perfect square? Re-state the question as: Is n an odd integer?

Statement 1: \(\sqrt{n}\) is an odd number. If \(\sqrt{n}\) is an odd number, n must be an odd number. (All powers of an odd number are odd. If a is odd, a^2 is odd, a^3 is odd, a^4 is odd, \(\sqrt{n}\), if integral, is odd etc.) Since we know that n is odd, this statement is sufficient.

Statement 2: \(y=\sqrt{5^{2(n-1)}}\) \(y=5^{n-1}\) Obviously, the number of factors of y is n. Do we know whether n is odd? No, we don't. Hence this statement alone is not sufficient.

Re: If n and y are positive integers and n represents the number [#permalink]

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This difficult question depends on an understanding of the properties of factors of a perfect square. The only way that a number can have an odd number of different total factors is if that number is a perfect square. Consider three numbers that are perfect squares, all of which have an odd number of total factors: 1, 9, and 16. The number 1 has only one unique factor (1); the number 9 has exactly three different factors (1, 3, 9); and 16 has five total factors (1, 16, 2, 8, 4). Statement (1) proves that n must be an odd integer so the information is sufficient to prove that y has an odd number of total unique factors and thus must be a perfect square. Statement (2) is more difficult to assess and requires that several different possible values of n be considered. For instance if n = 1 then y would be equal to 1 and it would indeed be a perfect square. However, if n = 2 then y would be equal to 5 which is not a perfect square. From those two values of n, it is clear that statement (2) is not sufficient and the correct answer is A, statement 1 alone is sufficient.

gmatclubot

Re: If n and y are positive integers and n represents the number
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07 Mar 2017, 18:24

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