divyadna wrote:
n is a multiple 18 and m is a multiple of 30, is mn a multiple of 120?
1) n is a multiple of 6
If n= 6 and m=30, then mn= 180 and 120 is not a factor of 180. Ans is NO.
If n= 12 and m=30, then mn= 360 and 120 is a factor of 360. Ans is YES.
We aren't getting a unique answer.
Statement I alone is insufficient.
2) m is a multiple of 12
n=18, m=60 (LCM of 12 & 30), nm= 1080 and 1080/120= 9.
Answer is YES.
Statement II alone is sufficient.
Option B is the answer
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If n is a multiple of 18 (provided in question)
and
n is a multiple of 6 (as per statement 1)
and
m is a multiple of 30 (as per statement 2), then how are we taking n = 6 as a number for checking if the condition is satisfied?
You took n to be 6 when you tried to analyze statement 1. But n cannot be 6 as n has to be a multiple of 18 (18, 36, 54 ....) as mentioned in the question
In my opinion, it should be B because if n is a multiple of 18 (2 x 3 x 3) and m is a multiple of 30 (2 x 3 x 5), then mn must be a multiple of 90, which is not a multiple of 12