sacchi wrote:
Hello,
Could anybody help me? Why is this wrong:
\((-2^{n})^{-2}\) = \(((-2)^n)^{-2}\) = \(-2^{-2n}\)
\((2^{-n})^{2}\) = \(((2)^{-n})^{2}\) = \(2^{-2n}\)
\(-2^{-2n}\) + \(2^{-2n}\) = 0
The answer I got was 0. I can follow the steps to get to D, but I'm not seeing my mistake, which originally led me to A.
Thanks!
Curious about this too because I also got zero. They ARE the same base.
\(-2^{-2n}\) + \(2^{-2n}\)
i.e.
\(2^{-2n}\) − \(2^{-2n}\) (commutative property of addition)
Therefore we can just factor:
\(2^{-2n}\) x (1 − 1) = \(2^{-2n}\) x (0) = 0
This is EXACTLY the same mathematical logic that allows us to say that
\(10^{13}\) − \(10^{11}\) = \(10^{11}\) x (\(10^{2}\) − 1) or \(10^{11}\) x (99)
Where am I going wrong?
EMPOWERgmatRichC DensetsuNo Bunuel