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it makes sense. Remove 7 and 11 from the product in the nominator, cause 77=7x11. Given that n is an integer, K should involve the numbers 2,3,5 and 13. Seems like K is 26

Oh my gosh...I can't believe it. I <b>did</b> remove 7 and 11 from the denonimator, but for some reason none of those number divided evenly for me. Eeek, I feel like such a dumb dumb!

This problem makes no sense to me. I don't even think the answer choices are correct. Hmm...maybe this source I'm using is not very reliable?!

If n is an integer and then which of the following could be the value of k?

n=(2*3*5*7*11*13)/77k

(A) 22 (B) 26 (C) 35 (D) 54 (E) 60

note that 7*11 = 77 and rewrite the problem by crossing out the 77's on the numerator and demoninator:
n = (2*3*5*13)/k
i also noticed that from the answer choices b) 26 is also shown in the numerator as 2*13...
if k = 26 then 2*13 can be crossed out leaving you with 3*5 or in other words an integer.
no work was necessary in terms of dividing out the choices to see if n was an integer.