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# If n is an integer, what is the least value of n for which 4^(-n)<1512

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Math Expert
Joined: 02 Sep 2009
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If n is an integer, what is the least value of n for which 4^(-n)<1512  [#permalink]

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29 Nov 2018, 00:28
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Difficulty:

45% (medium)

Question Stats:

57% (01:15) correct 43% (01:07) wrong based on 65 sessions

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If n is an integer, what is the least value of n for which $$4^{−n} < \frac{1}{512}$$ ?

A. 4
B. 5
C. 6
D. 7
E. 8

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If n is an integer, what is the least value of n for which 4^(-n)<1512  [#permalink]

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29 Nov 2018, 01:11
1
$$4^{-n}$$ = $$\frac{1}{4^n}$$ = $$\frac{1}{2^{2n}}$$

Also 512 = $$2^9$$

Then $$\frac{1}{2^{2n}}$$ < $$\frac{1}{2^9}$$

Least value of n should be 5. as $$2^{10}$$ = 1024

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If n is an integer, what is the least value of n for which 4^(-n)<1512   [#permalink] 29 Nov 2018, 01:11
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# If n is an integer, what is the least value of n for which 4^(-n)<1512

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