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If n is an integer, what is the least value of n for which 4^(-n)<1512

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If n is an integer, what is the least value of n for which 4^(-n)<1512  [#permalink]

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New post 28 Nov 2018, 23:28
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

58% (01:03) correct 42% (01:13) wrong based on 38 sessions

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If n is an integer, what is the least value of n for which 4^(-n)<1512  [#permalink]

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New post 29 Nov 2018, 00:11
\(4^{-n}\) = \(\frac{1}{4^n}\) = \(\frac{1}{2^{2n}}\)

Also 512 = \(2^9\)

Then \(\frac{1}{2^{2n}}\) < \(\frac{1}{2^9}\)

Least value of n should be 5. as \(2^{10}\) = 1024

B is the answer.
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If n is an integer, what is the least value of n for which 4^(-n)<1512 &nbs [#permalink] 29 Nov 2018, 00:11
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If n is an integer, what is the least value of n for which 4^(-n)<1512

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