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If n is the sum of the integers from 203 to 200, inclusive, then n =
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Updated on: 11 Mar 2017, 19:38
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If n is the sum of the integers from 203 to 200, inclusive, then n = A. 606 B. 456 C. 233 D. 3 E. 0
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Originally posted by Calichin on 11 Mar 2017, 16:00.
Last edited by Calichin on 11 Mar 2017, 19:38, edited 1 time in total.



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Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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11 Mar 2017, 16:28
X514 wrote: If n is the sum of the integers from 203 to 200, inclusive, then n =
A. 606 B. 456 C. 233 D. 3 E. 0 Notice that each positive term can be matched with a negative term to create a sum of ZERO. For example, ( 200) + 200 = 0, and ( 199) + 199 = 0We have: (203) + (202) + (201) + ( 200) + ( 199) + ( 198) + ...... + 198 + 199 + 200 = (203) + (202) + (201) + 0 + 0 ..... + 0 = 606 Answer: A Cheers, Brent
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Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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13 Mar 2017, 11:25
Hi X514, GMAT questions are rarely about doing 'lots of math', so it often helps to look for patterns in the way the prompt is designed (and avoid doing lots of math if possible). Here, we're asked for the sum of a LOT of integers  and if we tried to add them all up 'in order', then that would take a really long time (and we might end up making mistakes). Given the range of integers (203 to 200, inclusive), we should look for a pattern... 1 + 1 = 0 2 + 2 = 0 3 + 3 = 0 Etc. Notice all of the 0s that we'd end up with... and the numbers that would be 'left over'... 203, 202 and 201. The sum isn't that difficult to total now. Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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11 Mar 2017, 19:34
X514 wrote: If n is the sum of the integers from 203 to 200, inclusive, then n =
A. 606 B. 456 C. 233 D. 3 E. 0 X514Please provide OA!!!!!!!!!



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Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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14 Mar 2017, 13:38
This is another way to solve the problem 200  (203) = 403 + 1 = 404
n/2(a+l) 404/2(200  203) 606
Therefore, answer is A



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Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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02 Sep 2017, 08:08
Calichin wrote: If n is the sum of the integers from 203 to 200, inclusive, then n =
A. 606 B. 456 C. 233 D. 3 E. 0 Of the numbers from 203 to 200, the sum of numbers from 200 to 200 would be zero owing to the ve additions. So the sum is 203+202+201 = 606 Ans:A



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Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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02 Sep 2017, 23:21
This is a straight problem Numbers from 1 to 200 will cancel out number from 1 to 200 So we just have to add 201202203=606 Hence A is the answer



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If n is the sum of the integers from 203 to 200, inclusive, then n =
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16 Mar 2019, 16:41
Calichin wrote: If n is the sum of the integers from 203 to 200, inclusive, then n =
A. 606 B. 456 C. 233 D. 3 E. 0 Integers are from \(203\) to \(200\) inclusive. Sum of integers from \(200\) to \(200\) will get cancelled except \(0\). Only integers left are \(203, 202, 201, 0\). Sum of the above left integers \(= (203) + (202) +(201) + 0 = 203  202201 =  606\) Answer A



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Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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27 Dec 2019, 17:16
matthewsmith_89 wrote: This is another way to solve the problem 200  (203) = 403 + 1 = 404
n/2(a+l) 404/2(200  203) 606
Therefore, answer is A What is the (a+l) ? Why do you divide by 2?




Re: If n is the sum of the integers from 203 to 200, inclusive, then n =
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27 Dec 2019, 17:16






