Last visit was: 12 Dec 2024, 21:34 It is currently 12 Dec 2024, 21:34
Home
GMAT
Messages
Tests
Schools
Reviews
Social
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 12 Dec 2024
Posts: 97,851
Own Kudos:
685,423
 []
Given Kudos: 88,255
Products:
GMAT Club Tests Forum Quiz
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,851
Kudos: 685,423
 []
If n # z = n^2 - n^z - 2(z-2)^n for integers n and z, what is the valu 17 Mar 2016, 03:57
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

90% (00:41) correct 10% (00:44) wrong based on 135 sessions

History

Date
Time
Result
Not Attempted Yet
If \(n # z = n^2 - n^z - 2(z-2)^n\) for integers n and z, what is the value of 2#2?

A) -2
B) -1
C) 0
D) 1
E) 2
ShowHide Answer
Official Answer
C
User avatar
Kurtosis
User avatar
Current Student
Joined: 13 Apr 2015
Last visit: 10 Nov 2021
Posts: 1,419
Own Kudos:
4,732
Given Kudos: 1,228
Location: India
Products:
My Reviews
Posts: 1,419
Kudos: 4,732
If n # z = n^2 - n^z - 2(z-2)^n for integers n and z, what is the valu 17 Mar 2016, 07:12
Kudos
Add Kudos
Bookmarks
Bookmark this Post
\(2^2 - 2^2 - 2(2 - 2)^2 = 0\)

Answer: C
User avatar
nipunjain14
User avatar
Joined: 07 May 2015
Last visit: 12 Aug 2017
Posts: 159
Own Kudos:
77
Given Kudos: 21
Location: India
Schools: ISB '19 Kellogg '20 Yale '20 HEC Dec"18
GMAT 1: 660 Q48 V31
GPA: 3
Schools: ISB '19 Kellogg '20 Yale '20 HEC Dec"18
GMAT 1: 660 Q48 V31
Posts: 159
Kudos: 77
If n # z = n^2 - n^z - 2(z-2)^n for integers n and z, what is the valu 17 Mar 2016, 23:44
Kudos
Add Kudos
Bookmarks
Bookmark this Post
4-4-2(2-2)^2 = 0

Ans: C
User avatar
Badari
User avatar
Joined: 17 Nov 2014
Last visit: 05 Feb 2023
Posts: 53
Own Kudos:
70
Given Kudos: 166
Location: India
Posts: 53
Kudos: 70
If n # z = n^2 - n^z - 2(z-2)^n for integers n and z, what is the valu 19 Mar 2016, 08:27
Kudos
Add Kudos
Bookmarks
Bookmark this Post
2^2−2^2−2(2−2)^2=4-4=0

Answer: C
User avatar
BrushMyQuant
User avatar
Joined: 05 Apr 2011
Last visit: 09 Dec 2024
Posts: 2,044
Own Kudos:
2,297
Given Kudos: 100
Status:Tutor - BrushMyQuant
Location: India
Concentration: Finance, Marketing
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
GPA: 3
WE:Information Technology (Computer Software)
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
Posts: 2,044
Kudos: 2,297
If n # z = n^2 - n^z - 2(z-2)^n for integers n and z, what is the valu 08 Aug 2022, 09:41
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given that \(n # z = n^2 - n^z - 2(z-2)^n\) and we need to find the value of 2#2

To find 2#2 we need to compare what is before and after # in 2#2 and n#z

=> We need to substitute n with 2 and z with 2 in \(n # z = n^2 - n^z - 2(z-2)^n\) to get the value of 2#2

=> \(2 # 2 = 2^2 - 2^2 - 2(2-2)^2\) = 4 - 4 - 2*0 = 4-4 = 0

So, Answer will be C
Hope it helps!

Watch the following video to learn the Basics of Functions and Custom Characters

Moderator:
Bunuel
Math Expert
97851 posts