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Re: If p and n are positive integers and p > n, what is the
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Re: If p and n are positive integers and p > n, what is the
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13 Feb 2018, 19:44
Bunuel wrote: If p and n are positive integers and p>n, what is the remainder when p^2  n^2 is divided by 15?
First of all \(p^2  n^2=(p+n)(pn)\).
(1) The remainder when p + n is divided by 5 is 1. No info about pn. Not sufficient.
(2) The remainder when p  n is divided by 3 is 1. No info about p+n. Not sufficient.
(1)+(2) "The remainder when p + n is divided by 5 is 1" can be expressed as \(p+n=5t+1\) and "The remainder when p  n is divided by 3 is 1" can be expressed as \(pn=3k+1\).
Multiply these two > \((p+n)(pn)=(5t+1)(3k+1)=15kt+5t+3k+1\), now first term (15kt) is clearly divisible by 15 (r=0), but we don't know about 5t+3k+1. For example t=1 and k=1, answer r=9 BUT t=7 and k=3, answer r=0. Not sufficient.
OR by number plugging: if \(p+n=11\) (11 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=11\) and remainder upon division 11 by 15 is 11 BUT if \(p+n=21\) (21 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=21\) and remainder upon division 21 by 15 is 6. Not sufficient.
Answer: E. Hi Bunuel I plugged in numbers So i had chosen 31 which is divisble by 3 and 5. Hence, i chose C Could u pls explain what im missing out on?



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Re: If p and n are positive integers and p > n, what is the
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13 Feb 2018, 19:53
zanaik89 wrote: Bunuel wrote: If p and n are positive integers and p>n, what is the remainder when p^2  n^2 is divided by 15?
First of all \(p^2  n^2=(p+n)(pn)\).
(1) The remainder when p + n is divided by 5 is 1. No info about pn. Not sufficient.
(2) The remainder when p  n is divided by 3 is 1. No info about p+n. Not sufficient.
(1)+(2) "The remainder when p + n is divided by 5 is 1" can be expressed as \(p+n=5t+1\) and "The remainder when p  n is divided by 3 is 1" can be expressed as \(pn=3k+1\).
Multiply these two > \((p+n)(pn)=(5t+1)(3k+1)=15kt+5t+3k+1\), now first term (15kt) is clearly divisible by 15 (r=0), but we don't know about 5t+3k+1. For example t=1 and k=1, answer r=9 BUT t=7 and k=3, answer r=0. Not sufficient.
OR by number plugging: if \(p+n=11\) (11 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=11\) and remainder upon division 11 by 15 is 11 BUT if \(p+n=21\) (21 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=21\) and remainder upon division 21 by 15 is 6. Not sufficient.
Answer: E. Hi Bunuel I plugged in numbers So i had chosen 31 which is divisble by 3 and 5. Hence, i chose C Could u pls explain what im missing out on? One example is not enough to get sufficiency. Also, when asking a question, please be more specific and show you work.
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Re: If p and n are positive integers and p > n, what is the
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17 Feb 2018, 22:09
BANON wrote: If p and n are positive integers and p > n, what is the remainder when p^2  n^2 is divided by 15 ?
(1) The remainder when p + n is divided by 5 is 1. (2) The remainder when p  n is divided by 3 is 1. Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Since we have 2 variables (p and n) and 0 equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. Conditions 1) & 2): \(p + n = 6, p  n = 4 : p = 5, n = 1 : p^2  n^2 = 25  1 = 24\), its remainder is \(4\). \(p + n = 11, p  n = 7 : p = 9, n = 2 : p^2  n^2 = 81  4 = 77\), its remainder is \(2\). Thus, both conditions together are not sufficient, since the remainder is not unique. Therefore, E is the answer. In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.
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If p and n are positive integers and p > n, what is the
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01 Nov 2018, 21:55
@VertiasKarishma once we've narrowed down to C/E can we test the relationship in a simultaneous equation setup by adding p+n = 5Q+1 and pn = 3K+1 which works out to 2p = 5Q + 3K + 2 i.e. three variables requiring three assumptions hence unsolvable ? Thus E is the best answer.



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Re: If p and n are positive integers and p > n, what is the
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02 Nov 2018, 06:47
aadilismail wrote: @VertiasKarishma once we've narrowed down to C/E can we test the relationship in a simultaneous equation setup by adding p+n = 5Q+1 and pn = 3K+1 which works out to 2p = 5Q + 3K + 2 i.e. three variables requiring three assumptions hence unsolvable ? Thus E is the best answer. No, this does not work out. There is no point looking for p. We need p^2  n^2. Sometimes, you need less information to get the value of what you need even though you may not be able to get the value of each variable independently. p + n = 5Q + 1 p  n = 3K + 1 Now, what you need is (p + n)*(p  n) (p + n)*(p  n) = (5Q + 1)*(3K + 1) = 15QK + 3K + 5Q + 1 Is this divisible by 15? We know that the first term (15QK) is but what about the sum of the other 3 terms? We don't know since that depends on the values of Q and K. If K = 5 and Q = 3, this is not divisible by 15. If K = 3 and Q = 4, this is divisible by 15. Hence, both statements are insufficient.
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Re: If p and n are positive integers and p > n, what is the
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02 Nov 2018, 07:57
understood, thank you



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Re: If p and n are positive integers and p > n, what is the
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09 Dec 2018, 06:07
Bunuel wrote: If p and n are positive integers and p>n, what is the remainder when p^2  n^2 is divided by 15?
First of all \(p^2  n^2=(p+n)(pn)\).
(1) The remainder when p + n is divided by 5 is 1. No info about pn. Not sufficient.
(2) The remainder when p  n is divided by 3 is 1. No info about p+n. Not sufficient.
(1)+(2) "The remainder when p + n is divided by 5 is 1" can be expressed as \(p+n=5t+1\) and "The remainder when p  n is divided by 3 is 1" can be expressed as \(pn=3k+1\).
Multiply these two > \((p+n)(pn)=(5t+1)(3k+1)=15kt+5t+3k+1\), now first term (15kt) is clearly divisible by 15 (r=0), but we don't know about 5t+3k+1. For example t=1 and k=1, answer r=9 BUT t=7 and k=3, answer r=0. Not sufficient.
OR by number plugging: if \(p+n=11\) (11 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=11\) and remainder upon division 11 by 15 is 11 BUT if \(p+n=21\) (21 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=21\) and remainder upon division 21 by 15 is 6. Not sufficient.
Answer: E. Hello When the question stem says that The remainder when p + n is divided by 5 is 1, doesn't it implicitly place a constraint on pn? So dont we need to check pn too? While solving the question, I calculated p+n based on the criteria, pn for the chosen numbers and then p^2n^2 and finally checked divisibility. I started running out of time and had to guess and move.



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Re: If p and n are positive integers and p > n, what is the
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10 Dec 2018, 02:51
singh8891 wrote: Bunuel wrote: If p and n are positive integers and p>n, what is the remainder when p^2  n^2 is divided by 15?
First of all \(p^2  n^2=(p+n)(pn)\).
(1) The remainder when p + n is divided by 5 is 1. No info about pn. Not sufficient.
(2) The remainder when p  n is divided by 3 is 1. No info about p+n. Not sufficient.
(1)+(2) "The remainder when p + n is divided by 5 is 1" can be expressed as \(p+n=5t+1\) and "The remainder when p  n is divided by 3 is 1" can be expressed as \(pn=3k+1\).
Multiply these two > \((p+n)(pn)=(5t+1)(3k+1)=15kt+5t+3k+1\), now first term (15kt) is clearly divisible by 15 (r=0), but we don't know about 5t+3k+1. For example t=1 and k=1, answer r=9 BUT t=7 and k=3, answer r=0. Not sufficient.
OR by number plugging: if \(p+n=11\) (11 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=11\) and remainder upon division 11 by 15 is 11 BUT if \(p+n=21\) (21 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=21\) and remainder upon division 21 by 15 is 6. Not sufficient.
Answer: E. Hello When the question stem says that The remainder when p + n is divided by 5 is 1, doesn't it implicitly place a constraint on pn? So dont we need to check pn too? While solving the question, I calculated p+n based on the criteria, pn for the chosen numbers and then p^2n^2 and finally checked divisibility. I started running out of time and had to guess and move. VeritasKarishmaCan you please help me with this?



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Re: If p and n are positive integers and p > n, what is the
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11 Dec 2018, 05:01
singh8891 wrote: Bunuel wrote: If p and n are positive integers and p>n, what is the remainder when p^2  n^2 is divided by 15?
First of all \(p^2  n^2=(p+n)(pn)\).
(1) The remainder when p + n is divided by 5 is 1. No info about pn. Not sufficient.
(2) The remainder when p  n is divided by 3 is 1. No info about p+n. Not sufficient.
(1)+(2) "The remainder when p + n is divided by 5 is 1" can be expressed as \(p+n=5t+1\) and "The remainder when p  n is divided by 3 is 1" can be expressed as \(pn=3k+1\).
Multiply these two > \((p+n)(pn)=(5t+1)(3k+1)=15kt+5t+3k+1\), now first term (15kt) is clearly divisible by 15 (r=0), but we don't know about 5t+3k+1. For example t=1 and k=1, answer r=9 BUT t=7 and k=3, answer r=0. Not sufficient.
OR by number plugging: if \(p+n=11\) (11 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=11\) and remainder upon division 11 by 15 is 11 BUT if \(p+n=21\) (21 divided by 5 yields remainder of 1) and \(pn=1\) (1 divided by 3 yields remainder of 1) then \((p+n)(pn)=21\) and remainder upon division 21 by 15 is 6. Not sufficient.
Answer: E. Hello When the question stem says that The remainder when p + n is divided by 5 is 1, doesn't it implicitly place a constraint on pn? So dont we need to check pn too? While solving the question, I calculated p+n based on the criteria, pn for the chosen numbers and then p^2n^2 and finally checked divisibility. I started running out of time and had to guess and move. Note the information given to you about (p + n). The remainder when you divide it by 5 is 1. So (p+n) can be 6/11/16/21/26/31/36... etc. This gives us limitless values for (pn) with all possible different remainders when divided by 5. Yes, a particular small value for (p+n) could have put a constraint on (p  n). Such as (p+n) = 6. Now (p  n) could take a few values only.
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