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If p and q are consecutive even integers, is p>q? 1) p2 [#permalink]
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06 Jun 2007, 10:59
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If p and q are consecutive even integers, is p>q?
1) p2 and q+2 are consecutive even integers
2) p is prime



Intern
Joined: 04 Feb 2007
Posts: 37

a) True only for p </= 0 AND q <0> p2=2 & q+2=0 (Cons. Even) implies p>q for all [p, q].SUFF
b) P=PRIME and EVEN=2 implies q = 4. i.e. p<q...............SUFF.



Senior Manager
Joined: 03 Jun 2007
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I think it is B. I shall explain further if I am right



Director
Joined: 13 Mar 2007
Posts: 543
Schools: MIT Sloan

go with (A)
given p and q are consecutive even integers.
St1 : (p2) and (q+2) are consecutive even integers
now if we assume p>q,
p2 = q + 2 +2 => p = q + 6 ; but if p = q +6, p and q cannot be consecutive even
if we assume p<q> p = q+2  SUFF
St2 : p is prime => p = 2 , q can be either '0' or '4' INSUFF
Hence (A)



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Re: DS  consecutive even [#permalink]
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06 Jun 2007, 15:22
Caas wrote: If p and q are consecutive even integers, is p>q?
1) p2 and q+2 are consecutive even integers 2) p is prime
(1) if p2 and q+2 are consecutive also, then it MUST be the case that p>q. Suff.
(2) p is prime, then it´s =2. If p and q are consecutive even integers, then q = 0 or 4 (even integer can be +ve, ve, or 0), then we cannot know for sure whether p<>q. Insuff.
A.



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Joined: 17 Apr 2007
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Re: DS  consecutive even [#permalink]
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06 Jun 2007, 16:05
I'll go with A.
1) P2 and q+2 are consecutive even integers.
take the sample numbers where both numbers are positive and both are negative. you will see that p>q is always true for p2 and q +2 to be consecutive even integers. you can also test this eith {2, 0} and {0, 2}.  sufficient
2) p is prime. q could be 0 or 4. for 0 p >q holds up but not for 4.  not sufficient
Ankita



Manager
Joined: 02 Feb 2007
Posts: 117

Hey guys,
when i first looked at it, it also thought it was A, but if yo uthink about it's not enough to just say that p IS greater the q. In this case q is greater than p. (from the second option, where p is prime) The question asks if p>q, in this case you could you with certainty that it is not, therefore D, wither statement is suffiecient. One proves that p>q, and the other that P<q. Who cares if it is or not, point is that you could say it with certinty, and this is what GMAT wants.



CEO
Joined: 29 Mar 2007
Posts: 2560

Stmnt1:
p=6 q=4
62=4, 4+2=6 in this case p is greater than q. 6>4. You gotta take what you plugged in for p and q. Not the result of the subtraction.
B is insuff. While P has to be 2.
Q could be 0 or 4 since 0 is considered an even integer.
Answer A



Director
Joined: 30 Nov 2006
Posts: 591
Location: Kuwait

For this DS question, I will examine each statement alone.
What's asked: is p>q ?
What's given: p and q are consecutive even integers
What do we know?
either p = q+2 or p = q2
1) p2 and q+2 are consecutive even integers

if p = q2, then p2 = q4 which can never be a consecutive even integer after or before q+2
Thus, p = q+2 and hence p>q
Statement 1 is sufficient
2) p is prime

We know that p is even, and the only even prime integer is 2. Since q and p are consecutive even integers, q can be either 0 or 4.
Statement 2 is insufficient
My Answer: A



Senior Manager
Joined: 04 Mar 2007
Posts: 434

OA is A
Thank you all!



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Re: If p and q are consecutive even integers, is p>q? 1) p2 [#permalink]
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09 Apr 2017, 10:05
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Re: If p and q are consecutive even integers, is p>q? 1) p2
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