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Re: If p is a positive integer, is p a prime number?
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06 Jun 2014, 06:29

4

5

SOLUTION

If \(p\) is a positive integer, is \(p\) a prime number?

(1) \(p\) and \(p+1\) have the same number of factors.

Primes have 2 factors, 1 and itself, (the reverse is also true: if a positive integer has 2 factors, then it must be a prime). So, for the answer to the question to be YES, both \(p\) and \(p+1\) must be primes. Are there consecutive primes? Yes, 2 and 3.

Could we have a case when \(p\) and \(p+1\) have the same number of factors, and \(p\) is NOT a prime? Yes. For example, both 14 (not a prime) and 15 have four factors. Also, both 21 (not a prime) and 22 have four factors.

Not sufficient.

(2) \(p-1\) is a factor of \(p\).

\(p-1\) and \(p\) are consecutive integers. Consecutive integers do not share any common factor but 1. Therefore, \(p-1\) to be a factor of \(p\), \(p-1\) must be 1, which makes \(p\) equal to prime number 2. Sufficient.

If \(p\) is a positive integer, is \(p\) a prime number?

(1) \(p\) and \(p+1\) have the same number of factors. (2) \(p-1\) is a factor of \(p\).

Kudos for a correct solution.

ST. 1) p and P+1 have the same no. of factors. p=2 have two factors of 1 and 2 and p=p+1=3 also have two factors of 1 and 3

Also, P=14 have 1,14,2,7 as its factors and P=P+1 =15 have 1,15,3,5 as its factors.

now since P=2 ( a prime no.) and P=14 (a non prime) satisfy the given condition hence Insufficient

ST. 2) since p-1 is the factor of p therefore, we can write p as; p=k(p-1) ; where k is an integer.

re arranging the equation we have; p=k/(k-1) now since P is a positive integer. therefore the only of k that satisfy this equation is k=2 for which p=2 which is a prime no.

Re: If p is a positive integer, is p a prime number?
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06 Jun 2014, 13:57

1

Statement 1

If p=2; p+1 =3, both of them have 2 factors, in this case p is 2 and a prime number. (Remember : Prime Numbers only have 2 factors-1 & itself and 2,3 are the only consecutive prime numbers)

However if p=14 factors={1,2,7,14}, number of factors = 4

p+1=15 factors={1,3,5,15}, number of factors = 4

in this case p is not a Prime Number.

Hence Not Sufficient.

Statement 2

p-1 is a factor of p , that only happens when p-1=1 and p=2. (2 consecutive numbers with the smaller number being a factor of the larger number)

Re: If p is a positive integer, is p a prime number?
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15 Jun 2014, 22:39

1

WoundedTiger wrote:

Bunuel wrote:

If \(p\) is a positive integer, is \(p\) a prime number?

(1) \(p\) and \(p+1\) have the same number of factors. (2) \(p-1\) is a factor of \(p\)

St1: since p, p+1 are consecutive nos, they are co prime. There are only 1 set of nos which have same no of factors. No 2 has 1 &2 as factors, similarly 3 has 1 and 3 as factors.

For any other pair, the no of factors will not be the same.st1 is sufficient

St2: so we have p, p-1 are consecutive integers and are therefore co prime ie only 1 is a common factor Only combination where p-1 is a factor of p is 2,1. p=2 is prime and hence sufficient.

Ans is D

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Take P = 1, then P+1 = 2 It satisfies statement 1 But 1 is not a prime number

Take p=2, then p+1=3 Here P is a prime number. Hence statement one alone is not sufficient

Re: If p is a positive integer, is p a prime number?
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06 Jun 2014, 07:15

Bunuel wrote:

If \(p\) is a positive integer, is \(p\) a prime number?

(1) \(p\) and \(p+1\) have the same number of factors. (2) \(p-1\) is a factor of \(p\)

St1: since p, p+1 are consecutive nos, they are co prime. There are only 1 set of nos which have same no of factors. No 2 has 1 &2 as factors, similarly 3 has 1 and 3 as factors.

For any other pair, the no of factors will not be the same.st1 is sufficient

St2: so we have p, p-1 are consecutive integers and are therefore co prime ie only 1 is a common factor Only combination where p-1 is a factor of p is 2,1. p=2 is prime and hence sufficient.

Ans is D

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“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

If p is a positive integer, is p a prime number?
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01 Feb 2015, 14:52

Bunuel wrote:

SOLUTION

If \(p\) is a positive integer, is \(p\) a prime number?

(1) \(p\) and \(p+1\) have the same number of factors.

Primes have 2 factors, 1 and itself, (the reverse is also true: if a positive integer has 2 factors, then it must be a prime). So, for the answer to the question to be YES, both \(p\) and \(p+1\) must be primes. Are there consecutive primes? Yes, 2 and 3.

Could we have a case when \(p\) and \(p+1\) have the same number of factors, and \(p\) is NOT a prime? Yes. For example, both 14 (not a prime) and 15 have four factors. Also, both 21 (not a prime) and 22 have four factors.

Not sufficient.

(2) \(p-1\) is a factor of \(p\).

\(p-1\) and \(p\) are consecutive integers. Consecutive integers do not share any common factor but 1. Therefore, \(p-1\) to be a factor of \(p\), \(p-1\) must be 1, which makes \(p\) equal to prime number 2. Sufficient.

If \(p\) is a positive integer, is \(p\) a prime number?

(1) \(p\) and \(p+1\) have the same number of factors. (2) \(p-1\) is a factor of \(p\).

Kudos for a correct solution.

Target question:Is p a prime number?

Given: p is a positive integer

Statement 1: p and p+1 have the same number of factors. Let's TEST some values. There are several values of p that satisfy statement 1. Here are two: Case a: p = 2. This means that p+1 = 3. Notice that 2 and 3 both have the same number of factors (2 factors each). In this case, p IS prime Case b: p = 14. This means that p+1 = 15. Notice that 14 and 15 both have the same number of factors (4 factors each). In this case, p is NOT prime Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: p−1 is a factor of p Let's test some cases: If p = 3, then p-1 = 2. Is 2 a factor of 3? No. If p = 4, then p-1 = 3. Is 3 a factor of 4? No. If p = 5, then p-1 = 4. Is 4 a factor of 5? No. If p = 6, then p-1 = 5. Is 5 a factor of 6? No. . . . We can see that, if we keep going, p-1 will NEVER be a factor of p. Yet, statement 2 says that p-1 IS a factor of p. Let's test the two positive integers that we haven't yet tested: 2 and 1 If p = 2, then p-1 = 1. Is 1 a factor of 2? YES! So, p COULD equal 2 If p = 1, then p-1 = 0. Is 0 a factor of 1? No So, We can conclude that p MUST equal 2, which means p IS prime Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Re: If p is a positive integer, is p a prime number?
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19 May 2017, 16:18

1

Hi All,

This question can be solved by TESTing VALUES, but it will likely also require a bit of 'brute force' work. Sometimes the easiest/fastest way to get to the solution is to just put the pen on the pad and quickly list out the possibilities.

We're told that P is a POSITIVE INTEGER. We're asked if P is PRIME. This is a YES/NO question.

1) P and (P+1) have the same number of factors.

The information in this Fact might take a little bit of work to deal with, so let's brute force the possibilities until we find a couple of examples that match what we're told here:

We can now see two 'pairs' of numbers that have the SAME number of factors... 2 and 3; if P=2 then the answer to the question is YES 14 and 15; if P=14 then the answer to the question is NO Fact 1 is INSUFFICIENT

2) (P-1) is a factor of P.

Again, let's start at P=1 and see what occurs...

P=1 .. 0 is not a factor of 1 P=2 .. 1 IS a factor of 2 P=3 .. 2 is not a factor of 3 P=4 .. 3 is not a factor of 4 Etc.

At this point, we can stop working - larger values of P will continue to yield the same result. The ONLY time that (P-1) is a factor of P is when P=2. Thus, there is ONLY one answer to the question (and it happens to be YES). Fact 2 is SUFFICIENT

Re: If p is a positive integer, is p a prime number?
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25 May 2018, 23:48

Bunuel wrote:

SOLUTION

If \(p\) is a positive integer, is \(p\) a prime number?

(1) \(p\) and \(p+1\) have the same number of factors.

Primes have 2 factors, 1 and itself, (the reverse is also true: if a positive integer has 2 factors, then it must be a prime). So, for the answer to the question to be YES, both \(p\) and \(p+1\) must be primes. Are there consecutive primes? Yes, 2 and 3.

Could we have a case when \(p\) and \(p+1\) have the same number of factors, and \(p\) is NOT a prime? Yes. For example, both 14 (not a prime) and 15 have four factors. Also, both 21 (not a prime) and 22 have four factors.

Not sufficient.

(2) \(p-1\) is a factor of \(p\).

\(p-1\) and \(p\) are consecutive integers. Consecutive integers do not share any common factor but 1. Therefore, \(p-1\) to be a factor of \(p\), \(p-1\) must be 1, which makes \(p\) equal to prime number 2. Sufficient.

Please share your number properties tips HERE and get kudos point. Thank you.

Hi Bunuel

My question is how to quickly check that two consecutive number have same number of factors like 14-15. Because testing numbers is time taking. I am looking for quick way to find this thing out.